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When light shines on a compact disc it acts as a diffraction grating causing diffraction and dispersion of the light - Leaving Cert Physics - Question 7 - 2009

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When light shines on a compact disc it acts as a diffraction grating causing diffraction and dispersion of the light. Explain the underlined terms. Derive the diffr... show full transcript

Worked Solution & Example Answer:When light shines on a compact disc it acts as a diffraction grating causing diffraction and dispersion of the light - Leaving Cert Physics - Question 7 - 2009

Step 1

Explain the underlined terms.

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Answer

  1. Diffraction: This is the spreading out of a wave when it passes through a gap or around an obstacle. It allows light waves to bend and spread instead of continuing in a straight line.

  2. Dispersion: This refers to the splitting of white light into its constituent colors. It occurs when light passes through a prism or grating, separating it based on different wavelengths.

Step 2

Derive the diffraction grating formula.

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Answer

To derive the diffraction grating formula, we begin with the grating setup:

  • For constructive interference, the path difference is given by: dimesextsinheta=nimesextλd imes ext{sin} heta = n imes ext{λ}

Where:

  • d = distance between grating lines (1/number of lines per mm)
  • θ = angle of diffraction
  • n = order of diffraction
  • λ = wavelength of light

This relationship establishes how light interacts with the grating surface.

Step 3

Calculate (i) the wavelength of the green light;

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Using the formula, we have:

  • Distance to the screen, L = 90 cm = 0.9 m
  • Lines per mm = 80, hence d = 1/80 mm = 1.25 x 10^-5 m

The path difference for the third order image:

  • The distance between third order images is given as 23.8 cm = 0.238 m.

Using the small angle approximation:

  • extsin(heta)ext extoppositeexthypotenuse=23.8/290=0.264 ext{sin}( heta) ext{ } \approx \text{ } \frac{ ext{opposite}}{ ext{hypotenuse}} = \frac{23.8/2}{90} = 0.264

Substituting into the formula: extλ=dimesextsinhetan=(1.25×105)×0.26435.51×107m or 551 nm. ext{λ} = \frac{d imes ext{sin} heta}{n} = \frac{(1.25 \times 10^{-5}) \times 0.264}{3} \approx 5.51 \times 10^{-7} m \text{ or } 551 \text{ nm.}

Step 4

(ii) the maximum number of images that are formed on the screen.

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Answer

To find the maximum number of images:

The angle will not exceed 90 degrees, hence:

  • Using the formula: ndλn \leq \frac{d}{\text{λ}}

From earlier,

  • d for 80 lines/mm: d = 1.25×105m1.25 \times 10^{-5} m and λ found is 5.51×107m5.51 \times 10^{-7} m.

Calculating: n=(1.25×105)(5.51×107)22.7n = \frac{(1.25 \times 10^{-5})}{(5.51 \times 10^{-7})} \approx 22.7

Thus, the maximum number of images formed = 22 + 22 + 1 = 45.

Step 5

(iii) how the diffraction grating produces a spectrum;

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Answer

The diffraction grating produces a spectrum because:

  • Different colors of light have different wavelengths.
  • When white light passes through the grating, different wavelengths are diffracted at different angles, causing the separation of light into distinct colors.

Step 6

(iv) why a spectrum is not formed at the central (zero order) image.

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Answer

A spectrum is not formed at the central image (zero order) because:

  • At zero order, all colors constructively interfere, resulting in white light.
  • There is no path difference for light waves in the zero order, thus not allowing the separation into a spectrum.

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