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Distinguish between fission and fusion - Leaving Cert Physics - Question 8 - 2006

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Distinguish between fission and fusion. The core of our sun is extremely hot and acts as a fusion reactor. Why are large temperatures required for fusion to occur? ... show full transcript

Worked Solution & Example Answer:Distinguish between fission and fusion - Leaving Cert Physics - Question 8 - 2006

Step 1

Distinguish between fission and fusion.

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Answer

Fission is the splitting of a large nucleus into two smaller nuclei, resulting in a release of energy and neutrons. This process typically occurs in heavy elements like uranium or plutonium.

Fusion, on the other hand, is the process where two small nuclei combine to form a larger nucleus, which also releases energy. This process occurs naturally in stars, including our sun.

Step 2

Why are large temperatures required for fusion to occur?

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Answer

Large temperatures are required for fusion to occur due to the repulsive forces between positively charged nuclei. The high temperatures provide sufficient kinetic energy for the nuclei to overcome the Coulomb force of repulsion and come close enough for the strong nuclear force to take effect, leading to fusion.

Step 3

Write an equation for this nuclear reaction.

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The equation for the nuclear reaction involving two isotopes of helium can be written as:

\text{^3He} + \text{^3He} \rightarrow \text{^4He} + 2\text{^1H}

Step 4

What condition is necessary for this reaction to take place on earth?

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The necessary condition for this reaction to take place on Earth is the requirement of a large initial temperature, typically in the range of millions of degrees Celsius, to provide the necessary energy for the reaction.

Step 5

Calculate the energy released during this reaction.

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Answer

To calculate the energy released during the reaction, we can use the mass-energy equivalence principle:

E=mc2E = mc^2

where:

  • mass defect m=mass of reactantsmass of productsm = \text{mass of reactants} - \text{mass of products}.

Given:

  • mass of reactants: m3He=3.846×1027 kg(for two nuclei: 2×3.846×1027)m_{^3He} = 3.846 \times 10^{-27} \text{ kg} \left(\text{for two nuclei: } 2 \times 3.846 \times 10^{-27}\right)
  • mass of products: m4He+2m1Hm_{^4He} + 2m_{^1H}

Calculating the energy yields:

  • E=2.8×106×(2.998×108)2E = 2.8 \times 10^6 \times (2.998 \times 10^8)^2,
  • which gives approximately E=2.516×1012extJ2.52×1012extJE = 2.516 \times 10^{-12} ext{ J} \approx 2.52 \times 10^{-12} ext{ J}.

Step 6

Give one benefit of a terrestrial fusion reactor under each of the following headings:

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Answer

Fuel: Plentiful and readily available isotopes can be used, such as deuterium from seawater.

Energy: Vast amounts of energy are released, providing a significant energy source while producing minimal waste.

Pollution: Minimal radioactive waste is produced compared to fission reactors, leading to reduced environmental impact.

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