Lise Meitner and Marie Curie are the only women scientists to have elements named after them - Leaving Cert Physics - Question 9 - 2016
Question 9
Lise Meitner and Marie Curie are the only women scientists to have elements named after them.
In the case of Meitner this was for her work on fission and in the cas... show full transcript
Worked Solution & Example Answer:Lise Meitner and Marie Curie are the only women scientists to have elements named after them - Leaving Cert Physics - Question 9 - 2016
Step 1
fission: the breaking up of a large nucleus into smaller nuclei
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Fission refers to the process where a large nucleus (like Uranium-235) splits into smaller nuclei upon absorption of a neutron. This reaction releases a significant amount of energy and additional neutrons.
Step 2
radioactivity: the (spontaneous) disintegration of a nucleus
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Radioactivity is defined as the spontaneous decay of an unstable nucleus, leading to the emission of radiation, including alpha, beta, or gamma radiation.
Step 3
Calculate the energy released during this reaction.
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To find the energy released, we first calculate the mass defect:
Mass before reaction: 3.966×10−25 kg
Mass after reaction: 3.967×10−25 kg
Change in mass (loss): Δm=3.966×10−25−3.967×10−25=2.9×10−28 kg
Using Einstein's equation, E=mc2 and the speed of light, c=3×108 m/s:
E=(2.9×10−28)(3×108)2=2.6×10−11J
Step 4
How many of the neutrons emitted in a fission reaction must, on average, cause a further fission so that the reaction is self-sustaining and safe? Explain your answer.
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On average, one neutron is required to cause a subsequent fission event, resulting in a chain reaction. Thus, this is classified as an uncontrolled reaction.
Step 5
The neutrons emitted are sometimes passed through a moderator. Explain the function of the moderator.
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The moderator slows down the emitted neutrons, thus increasing their likelihood of causing further fission events, which is essential for maintaining a controlled chain reaction.
Step 6
Write a nuclear equation for the decay of radium-225.
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88225Ra→87221Ac+24He
Step 7
Calculate the number of radium-225 nuclei in a sample that has an activity of 5600 Bq.
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The decay constant ( \lambda ) can be found using: ( \lambda = \frac{0.693}{t_{1/2}}) where ( t_{1/2} = 14.9 \text{ days} = 1.29 \times 10^6 ext{ s} ):
λ=1.29×1060.693=5.38×10−7s−1
Using the formula for activity: ( A = \lambda N ):
5600=(5.38×10−7)N⟹N≈1.04×1010
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