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The SI unit is named in honour of Lord Kelvin - Leaving Cert Physics - Question 11 - 2008

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The SI unit is named in honour of Lord Kelvin. What is the temperature of the boiling point of water in kelvin? Define the newton, the unit of force. A force of 9 ... show full transcript

Worked Solution & Example Answer:The SI unit is named in honour of Lord Kelvin - Leaving Cert Physics - Question 11 - 2008

Step 1

What is the temperature of the boiling point of water in kelvin?

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Answer

The boiling point of water in kelvin is given as 373.15 K.

Step 2

Define the newton, the unit of force.

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Answer

The newton (N) is the force that gives a mass of 1 kg an acceleration of 1 m/s², expressed mathematically as: F=maF = ma.

Step 3

Using Newton’s laws of motion, calculate the change in momentum of the ball.

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Answer

The change in momentum (Δp) can be calculated using the formula:

extChangeinmomentum=Fimest ext{Change in momentum} = F imes t

Given the force is 9 kN and time is 0.6 ms:

Δp = 9 imes 10^3 imes 0.6 imes 10^{-3} = 5.4 ext{ kg m/s} $$.

Step 4

Name three different electromagnetic radiations.

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Answer

  1. X-rays
  2. Microwaves
  3. Ultra-violet rays

Step 5

What is the photoelectric effect?

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Answer

The photoelectric effect is the emission of electrons from a metal surface when it is exposed to light or radiation of a suitable frequency.

Step 6

Why was the quantum theory of light revolutionary?

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Answer

The quantum theory of light was revolutionary because it proposed that light travels in discrete packets of energy called photons, indicating that light has both particle and wave properties. This contradicted classical wave theory.

Step 7

What is the energy of a photon of this radiation?

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Answer

The energy (E) of a photon can be calculated using the formula: E=hfE = hf where h is Planck's constant and f is the frequency. Plugging in the values: E=(6.63imes1034extJs)(3.3imes1014extHz)=2.18imes1019extJ.E = (6.63 imes 10^{-34} ext{ J s}) (3.3 imes 10^{14} ext{ Hz}) = 2.18 imes 10^{-19} ext{ J}.

Step 8

Calculate the loss of mass during the reaction.

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Answer

The loss of mass can be calculated using Einstein's equation: E=mc2E = mc^2 Rearranging gives: m=Ec2m = \frac{E}{c^2} Substituting the given energy (E = 100 MJ = 1 imes 10^8 J) and the speed of light (c = 3 imes 10^8 m/s): m=1imes108(3imes108)2=1imes1089×10161.11×109extkg.m = \frac{1 imes 10^8}{(3 imes 10^8)^2} = \frac{1 imes 10^8}{9 \times 10^{16}} \approx 1.11 \times 10^{-9} ext{ kg}.

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