Photo AI

Read the following passage and answer the accompanying questions - Leaving Cert Physics - Question (a) - 2021

Question icon

Question (a)

Read-the-following-passage-and-answer-the-accompanying-questions-Leaving Cert Physics-Question (a)-2021.png

Read the following passage and answer the accompanying questions. In the beginning, nearly 14 billion years ago, all the space, matter and energy of the universe wa... show full transcript

Worked Solution & Example Answer:Read the following passage and answer the accompanying questions - Leaving Cert Physics - Question (a) - 2021

Step 1

State the quark composition of the proton.

96%

114 rated

Answer

The proton is made up of three quarks: two 'up' quarks and one 'down' quark, which can be denoted as:

u,u,du, u, d

Step 2

List the forces experienced by a proton in decreasing order of strength.

99%

104 rated

Answer

The forces experienced by a proton, in decreasing order of strength, are:

  1. Strong nuclear force
  2. Electromagnetic force
  3. Weak nuclear force
  4. Gravitational force

Step 3

The Planck constant relates energy and frequency. Express this unit in terms of metres, kilograms and seconds.

96%

101 rated

Answer

The Planck constant has a value of:

6.6imes1034extJs6.6 imes 10^{-34} ext{ J s}

To express this in terms of metres, kilograms, and seconds, we note that:

1 Joule (J) = 1 kg m² s⁻², hence:

6.6imes1034extJs=6.6imes1034extkgm2exts16.6 imes 10^{-34} ext{ J s} = 6.6 imes 10^{-34} ext{ kg m}^2 ext{s}^{-1}

Step 4

Write a nuclear equation for the pair annihilation of a proton and an antipron.

98%

120 rated

Answer

The nuclear equation for the pair annihilation of a proton (p) and an antiproton (p̄) is:

ightarrow 2 ext{ photons}$$

Step 5

A photon produces a muon anti-muon pair. Calculate the minimum energy of the photon in electronvolts.

97%

117 rated

Answer

Using the equation for energy-mass equivalence:

E=mc2E = mc^2

The mass of a muon (μ) is approximately:

mext(muon)imes2=2imes206extMeV/c2 =3.769×1028extkgm ext{ (muon)} imes 2 = 2 imes 206 ext{ MeV/c}^2 \ = 3.769 × 10^{-28} ext{ kg}

The energy of the photon is:

E=(3.769imes1028extkg)imes(3imes108extm/s)2=3.215×1011extJE = (3.769 imes 10^{-28} ext{ kg}) imes (3 imes 10^8 ext{ m/s})^2 = 3.215 × 10^{-11} ext{ J}

To convert this to electronvolts (eV), use:

1exteV=1.6imes1019extJ1 ext{ eV} = 1.6 imes 10^{-19} ext{ J}

Thus:

E=3.215×1011extJ1.6×1019extJ/eV=2.01×108exteVE = \frac{3.215 × 10^{-11} ext{ J}}{1.6 × 10^{-19} ext{ J/eV}} \\ = 2.01 × 10^{8} ext{ eV}

Step 6

In the Large Hadron Collider, how are the particles (a) accelerated, (b) maintained in circular motion?

97%

121 rated

Answer

(a) Particles in the Large Hadron Collider are accelerated using electric fields in the form of radiofrequency cavities, which increase the energy of the particles as they pass through.

(b) Particles are maintained in circular motion using magnetic fields generated by bending magnets, which keep the particles on a curved path.

Step 7

State two reasons why their experiments using this accelerator were of scientific significance.

96%

114 rated

Answer

  1. The first experimental verification of E=mc2E = mc^2, confirming the fundamental relationship between mass and energy.

  2. The transmutation using artificially accelerated particles which advanced the field of nuclear physics and contributed to our understanding of particle interactions.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;