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Calculate the energy stored in a 5 μF capacitor when a potential difference of 20 V is applied to it. - Leaving Cert Physics - Question 0 - 2007

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Calculate the energy stored in a 5 μF capacitor when a potential difference of 20 V is applied to it.

Worked Solution & Example Answer:Calculate the energy stored in a 5 μF capacitor when a potential difference of 20 V is applied to it. - Leaving Cert Physics - Question 0 - 2007

Step 1

Calculate the energy stored using the formula

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Answer

The energy stored in a capacitor can be calculated using the formula:

E=12CV2E = \frac{1}{2} C V^2

where:

  • EE is the energy in joules (J)
  • CC is the capacitance in farads (F)
  • VV is the potential difference in volts (V)

Step 2

Insert values into the formula

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Answer

Here, we have:

  • C=5μF=5×10−6FC = 5 \mu F = 5 \times 10^{-6} F
  • V=20VV = 20 V

Now substitute these values into the formula:

E=12(5×10−6F)(20V)2E = \frac{1}{2} (5 \times 10^{-6} F)(20 V)^2

Step 3

Perform the calculation

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Calculating further,

E=12(5×10−6)(400)E = \frac{1}{2} (5 \times 10^{-6}) (400)

E=12×2×10−4E = \frac{1}{2} \times 2 \times 10^{-4}

E=1×10−4JE = 1 \times 10^{-4} J

This can also be expressed in millijoules (mJ):

E=0.1mJE = 0.1 mJ

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