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Define the term force and state the unit of force - Leaving Cert Physics - Question 6 - 2016

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Define the term force and state the unit of force. Force is a vector quantity. Name another example of a vector quantity. The New Horizons spacecraft visited the m... show full transcript

Worked Solution & Example Answer:Define the term force and state the unit of force - Leaving Cert Physics - Question 6 - 2016

Step 1

Define the term force and state the unit of force.

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Answer

A force is defined as any interaction that, when unopposed, will change the motion of an object. It is a vector quantity, meaning it has both magnitude and direction. The unit of force is the Newton (N), which is defined as the force required to accelerate a one-kilogram mass by one meter per second squared.

Step 2

Force is a vector quantity. Name another example of a vector quantity.

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Answer

Another example of a vector quantity is velocity, which also has both magnitude and direction.

Step 3

State the factors which affect the size of the gravitational force between two bodies.

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Answer

The size of the gravitational force between two bodies is affected by the following factors:

  1. The mass of the first body.
  2. The mass of the second body.
  3. The distance between the centers of the two bodies.

Step 4

Use the equation below, which is taken from page 56 of the Formulae and Tables booklet, to calculate g, the acceleration due to gravity on the surface of Pluto.

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Answer

Using the formula g=GMr2g = \frac{GM}{r^2} where:

  • G=6.67×1011  N m2/kg2G = 6.67 \times 10^{-11} \; \text{N m}^2/\text{kg}^2
  • M=1.3×1026  kgM = 1.3 \times 10^{26} \; \text{kg}
  • r=1186  km=1.186×106  mr = 1186 \; \text{km} = 1.186 \times 10^{6} \; \text{m}, we can calculate:

g=(6.67×1011)(1.3×1026)(1.186×106)20.62  m/s2g = \frac{(6.67 \times 10^{-11}) (1.3 \times 10^{26})}{(1.186 \times 10^{6})^2} \approx 0.62 \; \text{m/s}^2

Step 5

Calculate the weight it would have on the surface of Pluto.

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Answer

Weight can be calculated using the formula: Weight=m×g\text{Weight} = m \times g where:

  • m=450  kgm = 450 \; \text{kg} (mass of the spacecraft)
  • g=0.62  m/s2g = 0.62 \; \text{m/s}^2 (acceleration due to gravity on Pluto)

Thus, Weight=450×0.62=279  N\text{Weight} = 450 \times 0.62 = 279 \; \text{N}

Step 6

Would you expect its weight at this position to be greater or less than it would be at the surface? Explain your answer.

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Answer

I would expect its weight to be less than it would be at the surface. This is because the gravitational force decreases with distance from the center of the planet. As the spacecraft is 1000 km from the surface, it is effectively further away, resulting in a smaller gravitational pull compared to when it is on the surface.

Step 7

Explain why Pluto's atmosphere exerts a very low pressure on its surface.

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Answer

Pluto's atmosphere exerts very low pressure because it is composed primarily of nitrogen, which is extremely thin. The atmospheric density is low due to its small mass and the fact that Pluto is far from the sun, resulting in very cold temperatures that cause most gases to freeze and diminish the atmosphere.

Step 8

Suggest a reason why solar panels were unsuitable in this case.

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Answer

Solar panels were unsuitable for the New Horizons mission because Pluto is very far from the sun. At such a distance, solar energy is significantly weaker, which would not generate enough power to operate the spacecraft’s instruments effectively.

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