Photo AI

Read the following passage and answer the accompanying questions - Leaving Cert Physics - Question 13 - 2022

Question icon

Question 13

Read-the-following-passage-and-answer-the-accompanying-questions-Leaving Cert Physics-Question 13-2022.png

Read the following passage and answer the accompanying questions. Europe's greatest scientist during the latter half of the seventeenth century, Christian Huygens, ... show full transcript

Worked Solution & Example Answer:Read the following passage and answer the accompanying questions - Leaving Cert Physics - Question 13 - 2022

Step 1

Diffraction is one of the wave properties of light. What is meant by diffraction?

96%

114 rated

Answer

Diffraction refers to the spreading of waves when they encounter an obstacle or pass through a gap. It illustrates how light behaves as a wave, allowing it to bend around corners and spread out after passing through narrow openings.

Step 2

Draw a labelled diagram of an experiment to demonstrate the wave nature of light.

99%

104 rated

Answer

An appropriate diagram would depict a coherent light source (like a laser) aimed at a double slit, resulting in a series of light and dark bands on a screen due to interference. Each slit should be labelled, as well as the light source and the resulting pattern.

Step 3

How do the observations demonstrate the wave nature of light?

96%

101 rated

Answer

The observations show interference patterns that are characteristic of waves. When light passes through the slits, it produces alternating bright and dark fringes on the screen, which can only be explained by the wave property of light interacting with itself.

Step 4

The eyepiece lens of Huygens' telescope was a converging lens arranged so as to produce a virtual image. Draw a ray diagram to show how a converging lens can produce a virtual image.

98%

120 rated

Answer

The ray diagram should illustrate a converging lens with rays coming from an object that is placed within the focal length of the lens, showing the rays diverging after passing through the lens and appearing to originate from a point behind the lens, thus forming a virtual image.

Step 5

The pendulum of Huygens' clock oscillated with a period of 2 s. Calculate the length of this pendulum.

97%

117 rated

Answer

Using the formula for the period of a pendulum, T=2pisqrtLgT = 2\\pi \\sqrt{\frac{L}{g}}, we can rearrange to find LL. With T=2T = 2 s and g=9.81m/s2g = 9.81 \, m/s^2:

L=gT24π2=9.81m/s2×(2s)24π20.993m.L = \frac{gT^2}{4\pi^2} = \frac{9.81 \, m/s^2 \times (2 \, s)^2}{4\pi^2} \approx 0.993 \, m.

Step 6

Calculate the mass of Saturn, the acceleration due to gravity on the surface of Saturn, and the period that Huygens' clock would have on the surface of Saturn.

97%

121 rated

Answer

Using the formula for gravitational force, F=GMR2F = \frac{GM}{R^2}, we find:

  1. Mass of Saturn:

    M=gR2GM = \frac{gR^2}{G}

    Substituting values:

    R=1.16×106m+5820×103m=1.22×107mR = 1.16 \times 10^6 \, m + 5820 \times 10^3 \, m = 1.22 \times 10^7 \, m

    M=9.81m/s2×(1.22×107)26.6742×10115.7×1026kg.M = \frac{9.81 \, m/s^2 \times (1.22 \times 10^7)^2}{6.6742 \times 10^{-11} } \approx 5.7 \times 10^{26} \, kg.

  2. Acceleration due to gravity on the surface of Saturn:

    g=GMR2g = \frac{GM}{R^2}

    g=6.6742×1011×5.7×1026(5820000)211.2m/s2.g = \frac{6.6742 \times 10^{-11} \times 5.7 \times 10^{26}}{(5820000)^2} \approx 11.2 \, m/s^2.

  3. Period of Huygens' clock on Saturn:
    Using the previously calculated length of the pendulum:

    T=2πLg2π0.99311.21.87s.T = 2\pi \sqrt{\frac{L}{g}}\approx 2\pi \sqrt{\frac{0.993}{11.2}} \approx 1.87 \, s.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;