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Benjamin Franklin began experimenting with electricity during the 18th century - Leaving Cert Physics - Question 11 - 2022

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Benjamin Franklin began experimenting with electricity during the 18th century. (i) What is electric current? (ii) Name an instrument used to measure electric curr... show full transcript

Worked Solution & Example Answer:Benjamin Franklin began experimenting with electricity during the 18th century - Leaving Cert Physics - Question 11 - 2022

Step 1

What is electric current?

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Answer

Electric current is defined as the flow of electric charge. It is measured in Amperes (A) and indicates how much charge is passing through a conductor in a specified time.

Step 2

Name an instrument used to measure electric current.

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Answer

An ammeter is an instrument used to measure electric current. It can also be referred to as a galvanometer or multimeter.

Step 3

A torch contains a battery, a light bulb and a switch. Draw a circuit diagram to show how these components are connected in a torch.

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Answer

To draw the circuit diagram:

  1. Represent the battery with two parallel lines, one longer (positive) and one shorter (negative).
  2. For the light bulb, use a circle with a cross inside.
  3. The switch can be represented by a break in the line with a dot where the two ends come close.
  4. Connect these components with straight lines representing wires.
  5. Make sure to show the battery connected to the switch and light bulb in series.

Step 4

The wires in a circuit are made of metal. Explain why.

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Wires in a circuit are made of metal because metals are good conductors of electricity. They have free electrons that can move easily, allowing the electric charge to flow with minimal resistance.

Step 5

Name the subatomic particle that is the charge carrier in a metal.

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Answer

The charge carrier in a metal is the electron.

Step 6

A charge of 30 C passes through a wire in a time of 6 s. Calculate the current flowing in the wire.

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Answer

Current (I) can be calculated using the formula:

I=QtI = \frac{Q}{t}

where:

  • QQ is the charge in Coulombs (C)
  • tt is the time in seconds (s)

Substituting the values:

I=30C6s=5AI = \frac{30 C}{6 s} = 5 A

Step 7

The wire has a resistance of 3 Ω. Calculate the potential difference (voltage) across the wire.

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Answer

The potential difference (V) can be calculated using Ohm's Law:

V=I×RV = I \times R

where:

  • II is the current (5 A from part vi)
  • RR is the resistance (3 Ω)

Substituting the values:

V=5A×3Ω=15VV = 5 A \times 3 \Omega = 15 V

Step 8

The 3 Ω wire is connected in parallel with another wire of resistance 2 Ω. Calculate the total resistance of the two wires in parallel.

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Answer

The total resistance (RTR_T) for two resistors in parallel can be found using the formula:

1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}

where R1=3ΩR_1 = 3 \Omega and R2=2ΩR_2 = 2 \Omega.

Substituting the values:

\frac{1}{R_T} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6} \\ R_T = \frac{6}{5} = 1.2 \Omega$$

Step 9

What is the resistance of a 3 m piece of the same wire?

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Answer

Resistance (RR) is directly proportional to the length of the wire. Thus, if a piece of wire of length 1.5 m has a resistance of 12 Ω, the resistance of a 3 m piece can be calculated as:

R=2×12Ω=24ΩR = 2 \times 12 \Omega = 24 \Omega

Step 10

State the relationship between the resistance of a wire and its cross-sectional area.

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Answer

The resistance of a wire is inversely proportional to its cross-sectional area. This means that as the cross-sectional area increases, the resistance decreases and vice versa.

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