Two resistors of resistance 4 Ω and 7 Ω are connected in series - Leaving Cert Physics - Question 10 - 2022

When resistors are connected in series, their total or combined resistance is simply the sum of their individual resistances. Hence:

$R_{total} = R_1 + R_2$

Substituting the given values:

$R_{total} = 4 \, \Omega + 7 \, \Omega = 11 \, \Omega$

Therefore, the combined resistance of the two resistors is 11 Ω.