a) State Hooke’s law - Leaving Cert Physics - Question 12 - 2011
Question 12
a) State Hooke’s law.
A body of mass 250 g vibrates on a horizontal surface and its motion is described by the equation $ a = -16 s $, where $ s $ is the displaceme... show full transcript
Worked Solution & Example Answer:a) State Hooke’s law - Leaving Cert Physics - Question 12 - 2011
Step 1
State Hooke’s law.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Hooke's Law states that the restoring force F is proportional to the displacement s from the equilibrium position, mathematically expressed as:
F=−ks
where k is the spring constant.
Step 2
Why does the body vibrate with simple harmonic motion?
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The body vibrates with simple harmonic motion because the acceleration a is directly proportional to the negative displacement s from the equilibrium position. This relationship can be observed in the given equation:
a=−16s
This implies that the force acting on the body is always directed towards the equilibrium position, thus fulfilling the criteria for simple harmonic motion (SHM).
Step 3
Calculate the frequency of vibration of the body?
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To calculate the frequency, we start from the equation of motion:
rac{d^2s}{dt^2} = -rac{16s}{1}
This indicates that rac{d^2s}{dt^2} = -rac{ ext{ω}^2 s}{1}, where extω2=16. Therefore, we find:
$$ and to find the frequency $ f $:
$$ f = rac{ ext{ω}}{2 ext{π}} = rac{4}{2 ext{π}} \
≈ 0.64 ext{ Hz} $.
Step 4
What is the magnitude of (i) the maximum force, (ii) the minimum force, which causes the body’s motion?
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
(i) To find the maximum force, we use:
F_{max} = m imes a_{max} = (0.250 ext{ kg}) imes (0.80) = 0.20 ext{ N} $$
(ii) The minimum force occurs when the body is at the equilibrium position, thus:
$$ F_{min} = 0 ext{ N} $$.
Join the Leaving Cert students using SimpleStudy...