Photo AI

A ball is kicked with an initial velocity of 20 m s⁻¹ at an angle of 50° to the horizontal - Leaving Cert Physics - Question (b) - 2021

Question icon

Question (b)

A-ball-is-kicked-with-an-initial-velocity-of-20-m-s⁻¹-at-an-angle-of-50°-to-the-horizontal-Leaving Cert Physics-Question (b)-2021.png

A ball is kicked with an initial velocity of 20 m s⁻¹ at an angle of 50° to the horizontal. Calculate the horizontal distance it travels in 1.2 seconds.

Worked Solution & Example Answer:A ball is kicked with an initial velocity of 20 m s⁻¹ at an angle of 50° to the horizontal - Leaving Cert Physics - Question (b) - 2021

Step 1

Calculate the horizontal component of the initial velocity

96%

114 rated

Answer

The horizontal component of the initial velocity can be calculated using the formula:

ux=uimesextcos(heta)u_x = u imes ext{cos}( heta)

where:

  • u=20extms−1u = 20 ext{ m s}^{-1} (initial velocity)
  • θ=50°\theta = 50° (angle to the horizontal)

Substituting the values:

ux=20imesextcos(50°)≈12.86extms−1u_x = 20 imes ext{cos}(50°) \approx 12.86 ext{ m s}^{-1}

Step 2

Calculate the horizontal distance traveled in 1.2 seconds

99%

104 rated

Answer

The horizontal distance can be calculated using the formula:

s=uximests = u_x imes t

where:

  • ux=12.86extms−1u_x = 12.86 ext{ m s}^{-1} (horizontal component of initial velocity)
  • t=1.2extsecondst = 1.2 ext{ seconds} (time of travel)

Substituting the values:

s=12.86imes1.2≈15.43extms = 12.86 imes 1.2 \approx 15.43 ext{ m}

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;