A car starts from rest and has an acceleration of 6 m s² - Leaving Cert Physics - Question b - 2021

To find the distance traveled by the car, we can use the following equation of motion:

$s = ut + \frac{1}{2}at^2$

where:

• $s$ is the distance,
• $u$ is the initial velocity (0 m/s, since the car starts from rest),
• $a$ is the acceleration (6 m/s²),
• $t$ is the time (12 s).

Plugging in the values:

$s = 0(12) + \frac{1}{2}(6)(12^2)$ $s = 0 + \frac{1}{2}(6)(144)$ $s = \frac{1}{2}(864)$ $s = 432 ext{ m}$

Therefore, the distance the car travels in 12 seconds is 432 meters.