Leaving Cert Physics Static Electricity: Coulomb's law may be written as

Coulomb's law may be written as $ F = \frac{1}{4\pi \epsilon_0} \frac{q_1 q_2}{d^2} $ - Leaving Cert Physics - Question g - 2021

Question g

$Coulomb's-law-may-be-written-as-$-F-=-\frac{1}{4\pi-\epsilon_0}-\frac{q_1-q_2}{d^2}-$-Leaving Cert Physics-Question g-2021.png$

Coulomb's law may be written as $ F = \frac{1}{4\pi \epsilon_0} \frac{q_1 q_2}{d^2} $. What do the letters F, q, and d stand for in this expression?

Worked Solution & Example Answer:Coulomb's law may be written as $ F = \frac{1}{4\pi \epsilon_0} \frac{q_1 q_2}{d^2} $ - Leaving Cert Physics - Question g - 2021

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Answer

F: The letter F represents the force between two charged objects. It is the electrostatic force exerted by one charge on another, following Coulomb's law, which quantifies the interaction between electric charges.
q: The letter q stands for the charge of the objects involved in the interaction. In this context, there are two charges, q₁ and q₂, which interact with each other.
d: The letter d denotes the distance between the centers of the two charges. This distance is crucial as the force between the charges diminishes with increasing distance, as explained by the inverse square relationship in Coulomb's law.