The temperature of an object is measured using a thermometer, which is based on the variation of its thermometric property - Leaving Cert Physics - Question 7 - 2008
Question 7
The temperature of an object is measured using a thermometer, which is based on the variation of its thermometric property.
(i) What is meant by temperature?
(ii) ... show full transcript
Worked Solution & Example Answer:The temperature of an object is measured using a thermometer, which is based on the variation of its thermometric property - Leaving Cert Physics - Question 7 - 2008
Step 1
What is meant by temperature?
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Answer
Temperature is defined as the measure of the thermal energy of an object, which corresponds to how hot or cold an object is. It reflects the average kinetic energy of the particles within a substance.
Step 2
What is the unit of temperature?
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Answer
The unit of temperature is degrees Celsius (°C) or Kelvin (K).
Step 3
Give an example of a thermometric property.
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An example of a thermometric property is the thermal expansion of liquids, which is exemplified by the rise of mercury in a thermometer.
Step 4
What is heat?
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Heat is the form of energy that is transferred between systems or objects with different temperatures, flowing from the hotter object to the cooler one until thermal equilibrium is reached.
Step 5
Name three ways in which heat can be transferred.
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The three ways in which heat can be transferred are conduction, convection, and radiation.
Step 6
Define specific heat capacity.
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Specific heat capacity is the amount of heat energy required to raise the temperature of 1 kg of a material by 1 K (or 1 °C). It is expressed by the formula: c=mΔTQ where Q is the heat added, m is the mass, and ΔT is the change in temperature.
Step 7
Calculate the rise in temperature of the water;
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Answer
The rise in temperature of the water can be calculated as follows:
ΔT=Tfinal−Tinitial=100°C−20°C=80°C.
Step 8
Calculate the energy required to heat the water to 100 °C;
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Answer
Using the formula for heat:
Q=mcΔT,
where:
m = 500 g (or 0.5 kg),
c = 4200 J/kg·K (specific heat capacity of water),
\Delta T = 80 °C,
we calculate:
Q=0.5×4200×80=168000J.
Step 9
Calculate the amount of energy the ring supplies every second;
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The power (energy per second) provided by the electric ring is given as 2 kW, which is equivalent to:
Power=2000W=2000J/s.
Step 10
Calculate the time it will take to heat the water to 100 °C.
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Using the formula for time:
t=PQ,
where:
Q = 168000 J (energy required) and
P = 2000 J/s (power supplied),
we find:
t=2000168000=84s.
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