Photo AI
Question 8
Electrons are emitted from metals during photoelectric emission, thermionic emission and radioactive decay. Distinguish between photoelectric and thermionic emissi... show full transcript
Step 1
Answer
Photoelectric emission occurs when photons of sufficient energy strike a metal surface, causing the ejection of electrons. This process is dependent on the frequency of the incident radiation.
Thermionic emission, on the other hand, refers to the emission of electrons from a heated material due to thermal energy. This occurs when the electrons gain enough energy to overcome the material's work function.
Step 2
Step 3
Answer
A line emission spectrum is produced when an element emits light of specific wavelengths, resulting in distinct lines on a spectrum.
This occurs in an atom when electrons transition between energy levels. When an electron moves from a higher energy level to a lower energy level, it emits a photon of light. The emitted photon corresponds to a specific energy difference between the two levels, leading to a specific wavelength.
Step 4
Step 5
Answer
(i) Point A represents the threshold frequency, which is the minimum frequency needed to eject electrons from the metal surface.
(ii) The slope of the graph represents Planck's constant (h), indicating the relationship between the kinetic energy of emitted electrons and the frequency of the incident radiation.
Step 6
Answer
First, we calculate the kinetic energy of the emitted electrons using the photoelectric equation.
Since the work function of magnesium is 3.68 eV:
.
To find the maximum velocity, we convert kinetic energy into joules:
E_k = rac{1}{2}mv^2
where is the mass of the electron, approximately .
Rearranging gives:
v = ext{sqrt}igg(rac{2E_k}{m}igg = ext{sqrt}igg(rac{2 imes 0.47 imes 1.6 imes 10^{-19}}{9.1 imes 10^{-31}}igg
Calculating yields the maximum velocity of the emitted electrons.
Step 7
Step 8
Answer
The minimum wavelength of an X-ray can be calculated using the equation:
ext{Energy} = rac{hc}{ ext{wavelength}}
For a 50 kV tube, the energy of the X-ray is 50 keV, which can be converted to joules, and we use Planck's constant (h) and the speed of light (c) to find the wavelength.
Step 9
Answer
Tungsten target: The tungsten target is used due to its high atomic number, which increases the efficiency of X-ray production.
Cooling fluid: A cooling fluid is used in the X-ray tube to dissipate the heat generated by the electrons colliding with the target.
Report Improved Results
Recommend to friends
Students Supported
Questions answered