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The Irish physicist George Stoney is most famous for introducing the term electron - Leaving Cert Physics - Question 12 - 2022

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The Irish physicist George Stoney is most famous for introducing the term electron. (i) State two properties of the electron. The photoelectric effect is the relea... show full transcript

Worked Solution & Example Answer:The Irish physicist George Stoney is most famous for introducing the term electron - Leaving Cert Physics - Question 12 - 2022

Step 1

State two properties of the electron.

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Answer

Two key properties of the electron are:

  • Electric charge: Electrons carry a negative charge of approximately -1.6 x 10^-19 coulombs.
  • Mass: The mass of an electron is approximately 9.11 x 10^-31 kg.

Step 2

Describe an experiment to demonstrate the photoelectric effect.

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Answer

To demonstrate the photoelectric effect, we can perform the following experiment:

Apparatus: Electroscope, zinc plate, UV lamp.

Method:

  1. Connect the zinc plate to the electroscope.
  2. Shine the UV lamp on the zinc plate for a specific duration.
  3. Observe the deflection of the electroscope’s needle.

Observation: If the frequency of the UV light is above the threshold frequency, the needle will deflect, indicating that electrons are being emitted from the zinc plate.

Step 3

Describe what happens if the frequency of the incident light is below the threshold frequency.

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If the frequency of the incident light is below the threshold frequency, the photoelectric effect does not occur. This means that no electrons are emitted from the surface of the metal, and the electroscope will show no deflection, as there are insufficient energy photons to release the electrons.

Step 4

Calculate the wavelength of light of this frequency.

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Answer

To calculate the wavelength, we can use the formula:

ext{Wavelength} = rac{c}{f}

Where:

  • cc is the speed of light (approximately 3 x 10^8 m/s).
  • ff is the frequency (6.5 x 10^{14} Hz).

Plugging in the values:

ext{Wavelength} = rac{3 imes 10^8 ext{ m/s}}{6.5 imes 10^{14} ext{ Hz}} = 4.6 imes 10^{-7} ext{ m}

Step 5

Calculate the energy of a photon of this frequency.

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Answer

The energy of a photon can be calculated using the formula:

E=hfE = hf

Where:

  • EE is the energy,
  • hh is Planck’s constant (6.63imes1034extJs6.63 imes 10^{-34} ext{ Js}),
  • ff is the frequency (6.5 x 10^{14} Hz).

Substituting the values:

E=(6.63imes1034extJs)imes(6.5imes1014extHz)=4.3imes1019extJE = (6.63 imes 10^{-34} ext{ Js}) imes (6.5 imes 10^{14} ext{ Hz}) = 4.3 imes 10^{-19} ext{ J}

Step 6

How are electrons produced in an X-ray tube?

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Answer

Electrons are produced in an X-ray tube through the process of thermionic emission, where a heated filament (cathode) releases electrons. These free electrons are then directed toward the target.

Step 7

How are electrons accelerated in an X-ray tube?

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Answer

Electrons are accelerated in an X-ray tube using a high voltage. The high voltage creates a strong electric field that propels the electrons toward the anode at high speeds.

Step 8

State one property of tungsten that makes it suitable to use as the target.

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Answer

Tungsten has a high melting point and a high specific heat capacity, making it suitable as a target in an X-ray tube as it can withstand the intense heat generated during electron bombardment.

Step 9

What material could be used to ensure that the X-rays do not escape from the X-ray tube?

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Answer

Lead can be used to ensure that the X-rays do not escape from the X-ray tube. Its dense and absorbent nature effectively shields against X-ray radiation.

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