Photo AI

A student used a cylindrical column of air closed at one end and a tuning fork of frequency 512 Hz in an experiment to measure the speed of sound in air - Leaving Cert Physics - Question 3 - 2014

Question icon

Question 3

A-student-used-a-cylindrical-column-of-air-closed-at-one-end-and-a-tuning-fork-of-frequency-512-Hz-in-an-experiment-to-measure-the-speed-of-sound-in-air-Leaving Cert Physics-Question 3-2014.png

A student used a cylindrical column of air closed at one end and a tuning fork of frequency 512 Hz in an experiment to measure the speed of sound in air. The follow... show full transcript

Worked Solution & Example Answer:A student used a cylindrical column of air closed at one end and a tuning fork of frequency 512 Hz in an experiment to measure the speed of sound in air - Leaving Cert Physics - Question 3 - 2014

Step 1

Draw a labelled diagram of the apparatus used in the experiment.

96%

114 rated

Answer

  1. Tuning Fork: A vibrating tuning fork held above the column of air.

  2. Column of Air: A cylindrical tube that is closed at one end filled with air.

  3. Adjustable Mechanism: A device or means (like a meter stick and calipers) to alter the length of the air column to find resonance.

    Ensure all components are clearly labeled in the diagram.

Step 2

Describe how the first position of resonance was found.

99%

104 rated

Answer

  1. Hold the Tuning Fork: The vibrating tuning fork is held over the open end of the air column.
  2. Increase Length of Column: Gradually increase the length of the air column starting from zero until the first resonance is observed.
  3. Identify Loudest Sound: The first position of resonance is reached when the loudest sound is heard from the column.

Step 3

Using the recorded data, calculate the speed of sound in air.

96%

101 rated

Answer

To calculate the speed of sound, use the formula:

v=4f(L+0.34)v = 4f(L + 0.34)

Where:

  • vv is the speed of sound,
  • ff is the frequency (512 Hz), and
  • LL is the length of the air column (16.2 cm = 0.162 m).

Substituting in the values:

v=4×512×(0.162+0.34)v = 4 \times 512 \times (0.162 + 0.34)

Calculating gives: v=4×512×0.502=1026.048 m/sv = 4 \times 512 \times 0.502 = 1026.048 \text{ m/s}

Hence, the speed of sound in air is approximately 338.8extm/s338.8 ext{ m/s}.

Step 4

Why was it necessary to measure the diameter of the air column?

98%

120 rated

Answer

It is necessary to measure the diameter of the air column because:

  1. Wave Adjustment: The diameter influences how sound waves resonate within the tube and the accuracy of the measurement.
  2. Error Correction: It allows for adjustments in calculations to account for end correction, where wave ends partially extend beyond the end of the tube.
  3. Proportionality: Sound wave behavior in tubes can vary based on diameter, affecting the speed calculations.

Step 5

Explain how this second student would find the speed of sound in air.

97%

117 rated

Answer

  1. Find Distance Between First Two Positions: Measure the length of the column of air for the first two positions of resonance denoted as L1L_1 and L2L_2.
  2. Double the Distance: The wavelength (λ\lambda) can be found using the formula: λ=2(L2L1)\lambda = 2(L_2 - L_1)
  3. Calculate Speed: Then, use the speed of sound formula: v=λTv = \frac{\lambda}{T}, where T is frequency. Substituting gives: v=2(L2L1)imesffv = \frac{2(L_2 - L_1) imes f}{f}, ultimately helping to determine the speed of sound in air.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;