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The human ear is most sensitive to sounds with frequencies between 2 kHz and 4 kHz - Leaving Cert Physics - Question (vi) (vii) (viii) - 2022

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Question (vi) (vii) (viii)

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The human ear is most sensitive to sounds with frequencies between 2 kHz and 4 kHz. One reason for this is that sounds in this range can cause resonance to occur in ... show full transcript

Worked Solution & Example Answer:The human ear is most sensitive to sounds with frequencies between 2 kHz and 4 kHz - Leaving Cert Physics - Question (vi) (vii) (viii) - 2022

Step 1

What is meant by resonance?

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Answer

Resonance refers to the transfer of energy between two objects of similar natural frequencies. In the context of the human ear, it involves the amplification of certain sound frequencies due to the matching frequencies of the ear canal.

Step 2

Draw a labelled diagram to show the first position of resonance for a sound wave in a pipe open at one end.

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Answer

To illustrate the first position of resonance in a pipe open at one end:

  1. Draw a horizontal line to represent the pipe.
  2. Label one end as the open end and the other as the closed end.
  3. At the open end, indicate an anti-node (maximum displacement).
  4. At the closed end, mark it as a node (minimum displacement).
  5. Clearly label both ends in the diagram.

Step 3

The frequency of a sound wave is 2800 Hz and it has a wavelength of 0.12 m. Calculate the speed of the wave.

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Answer

To calculate the speed of the wave, we use the formula:

v=fimeslambdav = f imes \\lambda

where:

  • vv is the speed of the wave,
  • ff is the frequency (2800 Hz),
  • lambda\\lambda is the wavelength (0.12 m).

Plugging in the values:
v=2800imes0.12=336m/sv = 2800 imes 0.12 = 336 \, m/s

Thus, the speed of the wave is 336 m/s.

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