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Practice Problems Simplified Revision Notes

Revision notes with simplified explanations to understand Practice Problems quickly and effectively.

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Practice Problems

Problems:


Problem 1:

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Question: A right-angled triangle has one side of length 33 cmcm and another side of length 44 cmcm. Find the length of the hypotenuse.


Problem 2:

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Question: In a right-angled triangle, the hypotenuse is 1010 cmcm, and one of the sides is 66 cmcm. Find the length of the other side.


Problem 3:

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Question: A ladder is leaning against a wall. The ladder is 1313 metersmeters long, and the bottom of the ladder is 55 metersmeters away from the wall. How high up the wall does the ladder reach?


Problem 4:

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Question: In a right-angled triangle, AngleAngle AA measures 30°30°, and the hypotenuse is 1010 cmcm. Find the length of the side opposite AngleAngle AA. Give your answer correct to two decimal places.


Problem 5:

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Question: In a right-angled triangle, the adjacent side to AngleAngle AA is 88 cmcm, and the hypotenuse is 1010 cmcm. Find the size of AngleAngle AA. Give your answer correct to one decimal place.


Problem 6:

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Question: In a right-angled triangle, AngleAngle AA measures 40°40°, and the side adjacent to AngleAngle AA is 77 cmcm. Find the length of the side opposite AngleAngle AA. Give your answer correct to two decimal places.


Solutions:


Problem 1:

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Question : A right-angled triangle has one side of length 33 cmcm and another side of length 44 cmcm. Find the length of the hypotenuse.

Step 1: Identify the sides of the triangle.

  • The given sides are the legs of the triangle.
  • The hypotenuse is the unknown side, labeled as cc.

Step 2: Write down the Pythagoras' Theorem formula. c2=a2+b2c^2 = a^2 + b^2 This formula states that the square of the hypotenuse (longest side) is equal to the sum of the squares of the other two sides.

Step 3: Substitute the known values into the formula. c2=32+42c^2 = 3^2 + 4^2

Step 4: Calculate the squares of the sides. c2=9+16c^2 = 9 + 16

Step 5: Add the squares. c2=25c^2 = 25

Step 6: Find cc by taking the square root of both sides. c=25=5cmc = \sqrt{25} = 5 \, \text{cm}

Explanation: The square root of 2525 gives the length of the hypotenuse. Since the hypotenuse is always the longest side, the answer makes sense.

Final Answer: The length of the hypotenuse is 55 cmcm.


Problem 2:

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Question: In a right-angled triangle, the hypotenuse is 1010 cmcm, and one of the sides is 66 cmcm. Find the length of the other side.

Step 1: Identify the sides of the triangle.

  • The hypotenuse is 1010 cmcm.
  • One leg is 66 cmcm.
  • The unknown side is labeled as bb.

Step 2: Write down the Pythagoras' Theorem formula. c2=a2+b2c^2 = a^2 + b^2 Since cc is the hypotenuse, rearrange the formula to solve for bb: b2=c2a2b^2 = c^2 - a^2

Step 3: Substitute the known values into the formula. b2=10262b^2 = 10^2 - 6^2

Step 4: Calculate the squares of the sides. b2=10036b^2 = 100 - 36

Step 5: Subtract the squares. b2=64b^2 = 64

Step 6: Find bb by taking the square root of both sides. b=64=8cmb = \sqrt{64} = 8 \, \text{cm}

Explanation: Taking the square root of 6464 gives the length of the unknown side. The answer fits within the context, as the hypotenuse should be the longest side.

Final Answer: The length of the other side is 88 cmcm.


Problem 3:

infoNote

Question: A ladder is leaning against a wall. The ladder is 1313 metersmeters long, and the bottom of the ladder is 55 metersmeters away from the wall. How high up the wall does the ladder reach?

Step 1: Identify the sides of the triangle.

  • The ladder forms the hypotenuse, which is 1313 metersmeters.
  • The distance from the wall to the base of the ladder is one side of the triangle, which is 55 metersmeters.
  • The height up the wall (unknown) is labeled as hh.

Step 2: Write down the Pythagoras' Theorem formula. c2=a2+b2c^2 = a^2 + b^2 Since cc is the hypotenuse, rearrange the formula to solve for hh (height): h2=c2b2h^2 = c^2 - b^2

Step 3: Substitute the known values into the formula. h2=13252h^2 = 13^2 - 5^2

Step 4: Calculate the squares of the sides. h2=16925h^2 = 169 - 25

Step 5: Subtract the squares. h2=144h^2 = 144

Step 6: Find hh by taking the square root of both sides. h=144=12metersh = \sqrt{144} = 12 \, \text{meters}

Explanation: The square root of 144144 gives the height the ladder reaches on the wall. The solution is reasonable, as the ladder's height is less than the ladder's length.

Final Answer: The ladder reaches 1212 metersmeters up the wall.


Problem 4:

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Question: In a right-angled triangle, AngleAngle AA measures 30°30°, and the hypotenuse is 1010 cmcm. Find the length of the side opposite AngleAngle AA. Give your answer correct to two decimal places.

Step 1: Identify the sides of the triangle.

  • Angle A is 30°30°.
  • The hypotenuse is 1010 cmcm.
  • The side opposite AngleAngle AA is unknown (x)(x).

Step 2: Choose the correct trigonometric ratio. Since the opposite side and hypotenuse are involved, use the Sine ratio: sin(A)=OppositeHypotenuse\sin(A) = \frac{\text{Opposite}}{\text{Hypotenuse}}

Step 3: Set up the equation. sin(30°)=x10\sin(30°) = \frac{x}{10}

Step 4: Solve for xx. First, find sin(30°)\sin(30°) using a calculator: sin(30°)=0.5\sin(30°) = 0.5 Now, substitute this value into the equation: 0.5=x100.5 = \frac{x}{10} Multiply both sides by 1010: x=0.5×10=5cmx = 0.5 \times 10 = 5 \, \text{cm}

Explanation: Using the sine function helps find the opposite side when the hypotenuse and angle are known. Multiplying by the hypotenuse gives the correct side length.

Final Answer: The length of the side opposite Angle A is 55 cmcm.


Problem 5:

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Question: In a right-angled triangle, the adjacent side to AngleAngle AA is 88 cmcm, and the hypotenuse is 1010 cmcm. Find the size of AngleAngle AA. Give your answer correct to one decimal place.

Step 1: Identify the sides of the triangle.

  • The adjacent side is 88 cmcm.
  • The hypotenuse is 1010 cmcm.
  • Angle A is unknown.

Step 2: Choose the correct trigonometric ratio. Since the adjacent side and hypotenuse are involved, use the Cosine ratio: cos(A)=AdjacentHypotenuse\cos(A) = \frac{\text{Adjacent}}{\text{Hypotenuse}}

Step 3: Set up the equation. cos(A)=810\cos(A) = \frac{8}{10}

Step 4: Simplify and solve for AA. First, calculate the fraction: cos(A)=0.8\cos(A) = 0.8 Now, find AngleAngle AA using the inverse cosine function: A=cos1(0.8)A = \cos^{-1}(0.8) Using a calculator: A36.87°A \approx 36.87°

Explanation: The inverse cosine function helps find the angle when the sides are known. The calculator's inverse function is used to work backward from the ratio to the angle.

Final Answer: AngleAngle AA is approximately 36.9°36.9°.


Problem 6:

infoNote

Question: In a right-angled triangle, AngleAngle AA measures 40°40°, and the side adjacent to AngleAngle AA is 77 cmcm. Find the length of the side opposite AngleAngle AA. Give your answer correct to two decimal places.

Step 1: Identify the sides of the triangle.

  • Angle A is 40°40°.
  • The adjacent side is 77 cmcm.
  • The opposite side is unknown (x)(x).

Step 2: Choose the correct trigonometric ratio. Since the opposite and adjacent sides are involved, use the TangentTangent ratio: tan(A)=OppositeAdjacent\tan(A) = \frac{\text{Opposite}}{\text{Adjacent}}

Step 3: Set up the equation. tan(40°)=x7\tan(40°) = \frac{x}{7}

Step 4: Solve for xx. First, find tan(40°)\tan(40°) using a calculator: tan(40°)0.8391\tan(40°) \approx 0.8391 Now, substitute this value into the equation: 0.8391=x70.8391 = \frac{x}{7} Multiply both sides by 77: x=0.8391×7=5.87cmx = 0.8391 \times 7 = 5.87 \, \text{cm}

Explanation: Using the tangent function helps find the opposite side when the adjacent side and angle are known. Multiplying by the adjacent side gives the correct side length.

Final Answer: The length of the side opposite AngleAngle AA is 5.875.87 cmcm.


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