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Practice Problems Simplified Revision Notes

Revision notes with simplified explanations to understand Practice Problems quickly and effectively.

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Practice Problems

Problems:


Problem 1:

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Question: You roll two dice. How many different outcomes are possible? List all the possible outcomes.

Explanation: Rolling two dice means there are many possible results. We need to think about all the different ways the dice can land. Let's list all the possible outcomes to see how many there are.


Problem 2:

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Question: You spin two spinners. Spinner 11 has 44 colours: Red, Blue, Green, Yellow. Spinner 22 has 33 numbers: 1,2,31, 2, 3. Use a two-way table to find all the possible outcomes.

Explanation: When you spin two spinners, each with different options, the outcomes can be a bit tricky to keep track of. A two-way table helps us see all the possible results clearly.


Problem 3:

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Question: A student can choose one of 44 sandwichessandwiches, one of 33 drinksdrinks, and one of 33 dessertsdesserts for lunch. How many different lunch combinations can be made? Show your working.

Explanation: When choosing a lunch, there are many combinations possible, depending on the choices for sandwiches, drinks, and desserts. We'll figure out how many different lunches you can make by multiplying the choices together.


Solutions:


Problem 1:

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Question: You roll two dice. How many different outcomes are possible? List all the possible outcomes.

  1. Step 1: Start with the first die. It has 66 possible outcomes: 1,2,3,4,5,1, 2, 3, 4, 5, or 66. We list these outcomes to make sure we consider all possibilities for the first die.
  2. Step 2: For each outcome on the first die, think about what can happen with the second die. It also has 66 possible outcomes: 1,2,3,4,5,1, 2, 3, 4, 5, or 66. By considering each number from the second die for every outcome from the first die, we ensure that we capture all possible combinations.
  3. Step 3: List all the combinations:
  • If the first die shows 11, the second die can show 1,2,3,4,51, 2, 3, 4, 5, or 66. That gives us the pairs (1,1),(1,2),(1,3),(1,4),(1,5)(1,1), (1,2), (1,3), (1,4), (1,5), and (1,6)(1,6).

  • We repeat this process for every number on the first die, pairing it with each possible number from the second die. The full list of outcomes is:

  • (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

  • (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

  • (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

  • (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

  • (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

  • (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

  1. Step 4: Count all the pairs. You should see that there are 3636 differentdifferent outcomesoutcomes. Why We Do Each Step:
  • Step 1 and Step 2: Listing the outcomes for each die helps us to visualise all possible results.
  • Step 3: Pairing each outcome from the first die with each outcome from the second ensures we don't miss any combinations.
  • Step 4: Counting all the pairs gives us the total number of possible outcomes. Answer: There are 3636 possiblepossible outcomesoutcomes when you roll two dice.
infoNote

Exam Tip: When listing outcomes, it's easy to miss some if you're not careful. Try to be systematic—work through each number on the first die, pairing it with all the possibilities from the second die. This way, you won't leave any outcomes out.


Problem 2:

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Question: You spin two spinners. Spinner 11 has 44 colourscolours: Red,Blue,Green,YellowRed, Blue, Green, Yellow. Spinner 22 has 33 numbersnumbers: 1,2,31, 2, 3. Use a two-way table to find all the possible outcomes.

  1. Step 1: Start by setting up your two-way table. One side of the table will list the colours from Spinner 11 (Red,Blue,Green,Yellow)(Red, Blue, Green, Yellow), and the other side will list the numbers from Spinner 22 (1,2,3)(1, 2, 3). This helps us organise the information clearly and allows us to see all possible outcomes at a glance. The table looks like this:
Colour NumberColour \ Number112233
RedRedR1R1R2R2R3R3
BlueBlueB1B1B2B2B3B3
GreenGreenG1G1G2G2G3G3
YellowYellowY1Y1Y2Y2Y3Y3
  1. Step 2: Now, let's fill in the table. Each cell in the table represents one outcome. For example:
  • If Spinner 11 lands on RedRed and Spinner 22 lands on 11, the outcome is R1R1.
  • If Spinner 11 lands on BlueBlue and Spinner 22 lands on 22, the outcome is B2B2. By filling in each cell, we ensure that every combination of colour and number is accounted for. The completed table should look like this:
Colour NumberColour \ Number112233
RedRedR1R1R2R2R3R3
BlueBlueB1B1B2B2B3B3
GreenGreenG1G1G2G2G3G3
YellowYellowY1Y1Y2Y2Y3Y3
  1. Step 3: Count all the outcomes in the table. There are 44 rowsrows and 33 columnscolumns, so 4Ă—3=124 Ă— 3 = 12 outcomes in total. This multiplication confirms that we have considered all possibilities. Why We Do Each Step:
  • Step 1: Setting up the table helps us organise our work and make sure we're considering every possibility.
  • Step 2: Filling in each cell ensures we don't miss any combinations.
  • Step 3: Counting the outcomes verifies that we've accounted for every possibility. Answer: There are 1212 possiblepossible outcomesoutcomes when you spin both spinners.
infoNote

Exam Tip: A two-way table is like a grid that organises your options. If you're dealing with two things (like colours and numbers), this is a great way to see all the possibilities at once. Just be sure to double-check that each box is filled in correctly.


Problem 3:

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Question: A student can choose one of 44 sandwichessandwiches, one of 33 drinksdrinks, and one of 33 dessertsdesserts for lunch. How many different lunch combinations can be made? Show your working.

  1. Step 1: Let's break down the choices:
  • Sandwiches: You have 44 options.
  • Drinks: You have 33 options.
  • Desserts: You have 33 options. Listing the number of options helps us see how many choices are available for each part of the meal.
  1. Step 2: To find out how many different lunch combinations you can make, multiply the number of options for each part of the meal:
  • First, multiply the number of sandwiches by the number of drinks: 4Ă—3=124 Ă— 3 = 12. This gives us the total number of combinations for sandwiches and drinks.
  • Then, multiply that result by the number of desserts: 12Ă—3=3612 Ă— 3 = 36. This final multiplication includes the dessert choices, giving us the total number of lunch combinations.
  1. Step 3: So, by multiplying the choices together, you find that there are 3636 possible $$combinations of a sandwich, drink, and dessert. Why We Do Each Step:
  • Step 1: Listing the choices ensures we know what options are available.
  • Step 2: Multiplying the options for each part of the meal counts all possible combinations.
  • Step 3: The final multiplication gives the total number of different lunch combinations. Answer: There are 3636 differentdifferent lunchlunch combinationscombinations you can make.
infoNote

Exam Tip: When multiplying choices, it's important to remember that you're finding the total number of combinations. Think of it as stacking choices on top of each other. First, you pick a sandwich, then you pick a drink, and finally, you pick a dessert. By multiplying, you're counting all the different ways you could make those choices.


infoNote

Final Tips for Exam Success:

  • Be Patient: Take your time with each step. Rushing can lead to mistakes, especially when listing outcomes or multiplying choices.
  • Double-Check: Always double-check your work. It's easy to miss a step or forget a combination, so go back and review what you've done.
  • Practice Regularly: The more you practice, the more confident you'll become. Try working on different problems to improve your skills.

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