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This experiment investigates how the concentration of sodium thiosulphate affects the rate of reaction with hydrochloric acid.
The reaction produces sulfur, which forms a cloudy precipitate that obscures a cross marked on paper placed beneath the reaction flask. The time taken for the cross to disappear is used to measure the rate of reaction.
By varying the concentration of sodium thiosulphate while keeping other conditions constant, the relationship between concentration and reaction rate is examined.
The reaction is as follows:
Concentration of Sodium Thiosulphate (M) | Reaction Time (s) | 1/Time (s⁻¹) |
---|---|---|
0.1 | 43 | 0.0233 |
0.08 | 52 | 0.0192 |
0.06 | 71 | 0.0141 |
0.04 | 114 | 0.0088 |
0.02 | 270 | 0.0037 |
Increasing the concentration decreases the reaction time, meaning the cross disappears faster.
The reaction rate increases with higher concentrations of sodium thiosulphate.
The rate of reaction is inversely proportional to time, meaning that a faster reaction corresponds to a shorter time, and using 1/time allows for a direct comparison of rates.
The graph shows that the reaction rate is directly proportional to the concentration of sodium thiosulphate, confirming that higher concentrations increase the rate of reaction.
Safety glasses must be worn, and the experiment should be carried out in a well-ventilated area to avoid inhaling sulfur dioxide gas produced during the reaction.
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