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Triangle with One Point at (0,0) Simplified Revision Notes

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Triangle with One Point at (0,0)

What is a Triangle with One Vertex at (0,0)(0, 0)?

In coordinate geometry, a triangle with one vertex at the origin (0,0)(0, 0) is a common configuration for problems involving geometry and coordinate-based calculations.

The other two vertices of the triangle, say (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), are located elsewhere in the Cartesian plane.

This setup simplifies calculations for:

  1. Area of the triangle.
  2. Length of the sides.
  3. Slopes and equations of the sides.

Area of the Triangle

The formula for the area of a triangle with vertices at (0,0)(0, 0), (x1,y1)(x_1, y_1), and (x2,y2)(x_2, y_2) is:

Area=12x1y2x2y1\text{Area} = \frac{1}{2} \left| x_1y_2 - x_2y_1 \right|

Length of the Sides

  1. From (0,0)(0, 0) to (x1,y1)(x_1, y_1):
Length=x12+y12\text{Length} = \sqrt{x_1^2 + y_1^2}
  1. From (0,0)(0, 0) to (x2,y2)(x_2, y_2):
Length=x22+y22\text{Length} = \sqrt{x_2^2 + y_2^2}
  1. From (x1,y1)(x_1, y_1) to (x2,y2)(x_2, y_2):
Length=(x2x1)2+(y2y1)2\text{Length} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Equations of the Sides

  1. From (0,0)(0, 0) to (x1,y1x_1, y_1)****: Slope m=y1x1m = \frac{y_1}{x_1}, equation y=mxy = mx

  2. From (0,0)(0, 0) to (x2,y2)(x_2, y_2): Slope m=y2x2m = \frac{y_2}{x_2}, equation y=mxy = mx

  3. From (x1,y1)(x_1, y_1) to (x2,y2)(x_2, y_2): Slope m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, equation: yy1=m(xx1)y - y_1 = m(x - x_1)


Worked Examples

infoNote

Example 1: Find the Area of a Triangle

Problem: Find the area of a triangle with vertices (0,0),(3,4)(0, 0), (3, 4), and (6,2)(6, 2)


Solution:

Step 1: Use the area formula:

Area=12x1y2x2y1\text{Area} = \frac{1}{2} \left| x_1y_2 - x_2y_1 \right|

Step 2: Substitute (x1,y1)=(3,4)(x_1, y_1) = (3, 4) and (x2,y2)=(6,2)(x_2, y_2) = (6, 2)

Area=123(2)6(4)=12624=12×18=9\text{Area} = \frac{1}{2} \left| 3(2) - 6(4) \right| = \frac{1}{2} \left| 6 - 24 \right| = \frac{1}{2} \times 18 = 9

Answer: The area is 99 square units.


infoNote

Example 2: Find the Length of a Side

Problem: Find the length of the side from (0,0)(0, 0) to (3,4)(3, 4)


Solution:

Step 1: Use the distance formula:

Length=x12+y12\text{Length} = \sqrt{x_1^2 + y_1^2}

Step 2: Substitute (x1,y1)=(3,4)(x_1, y_1) = (3, 4)

Length=32+42=9+16=25=5\text{Length} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5

Answer: The length is 55 units.


Summary

  • A triangle with one vertex at (0,0)(0, 0) simplifies calculations in coordinate geometry.
  • Key formulas:
    • Area: 12x1y2x2y1\frac{1}{2} \left| x_1y_2 - x_2y_1 \right|
    • Side lengths: Use the distance formula for each pair of points.
    • Sides' equations: Use the slope and point-slope formulas.
  • Practice applying these techniques to master solving geometric problems.
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