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Trigonometric Functions Simplified Revision Notes

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Trigonometric Functions

Derivatives of Basic Trigonometric Functions

The derivatives of the three fundamental trigonometric functions are essential in calculus and can be found in the log tables:

ddx[cos(x)]=sin(x)\frac{d}{dx} \left[ \cos(x) \right] = -\sin(x) ddx[sin(x)]=cos(x)\frac{d}{dx} \left[ \sin(x) \right] = \cos(x) ddx[tan(x)]=sec2(x)\frac{d}{dx} \left[ \tan(x) \right] = \sec^2(x)

For more complex trigonometric functions, differentiation often requires the chain rule in addition to these basic derivative rules. This is particularly useful when differentiating functions of the form sin(g(x))\sin(g(x)), cos(g(x))\cos(g(x)), tan(g(x))\tan(g(x)), where g(x)g(x) is a function of xx.

Example

infoNote

Differentiate cos(7x3)\cos{(7x-3)}

Identify an inner and outer function :

v=7x3v=7x-3u=cos(v)u=\cos(v)

Differentiate both functions :

v=7v'=7u=sin(v)u'=-\sin(v)

Apply chain rule :

uv=7sin(v)=7sin(v)=7sin(7x3)\begin{align*} u' \cdot v' &= 7 \cdot -\sin(v) \\\\ &= -7\sin(v) \\\\ &= -7\sin(7x-3) \end{align*}

Example

infoNote

Differentiate sin2(5x+2)\sin^2(5x+2)

When taking powers of trigonometric functions, the general rules applies :

sinn(x)=(sin(x))n\sin^n(x)=\left( \sin(x)\right)^n

We can rewrite the expression as :

[sin(5x+2)]2\left[ \sin(5x+2) \right]^2

Identify an inner and outer function :

v=sin(5x+2)v=\sin(5x+2) u=v2u=v^2

Differentiate both functions :

vv'

infoNote
v=sin(u1)v= \sin(u_1)u1=5x+2u_{1}= 5x+2v=cos(u1)v'= \cos{(u_1)}u1=5u_1'=5vu1=cos(u1)5=5cos(5x+2)\begin{align*} v' \cdot u_1' &= \cos(u_1) \cdot 5 \\\\ &= 5 \cos(5x+2) \end{align*}

uu'

infoNote
u=v2u=v^2u=2vu'=2v

Apply chain rule :

uv=2v5cos(5x+2)=2(sin(5x+2))5cos(5x+2)=10sin(5x+2)cos(5x+2)\begin{align*} u' \cdot v' &= 2v \cdot 5 \cos(5x+2) \\\\ &= 2(\sin(5x+2)) \cdot 5 \cos(5x+2) \\\\ &= 10\sin(5x+2)\cos(5x+2) \end{align*}

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