Photo AI

Last Updated Sep 27, 2025

Combinations Simplified Revision Notes

Revision notes with simplified explanations to understand Combinations quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

316+ students studying

Combinations

Combinations

Combinations are a method in combinatorics used to calculate the number of ways to select a group of items from a larger set without considering the order of selection.

Formula

The formula for combinations is:

C(n,r)=n!r!(nr)!C(n, r) = \frac{n!}{r!(n-r)!}

Where:

  • nn is the total number of items.
  • rr is the number of items to select.
  • !! represents factorial, which is the product of all positive integers up to that number (e.g., 5!=5×4×3×2×15! = 5 \times 4 \times 3 \times 2 \times 1). Combinations differ from permutations because the order of selection does not matter in combinations, whereas it does in permutations.

Steps to Calculate Combinations

  1. Determine nn and rr: Identify the total number of items (nn) and the number of items to select (rr).

  2. Apply the Formula: Substitute the values of nn and rr into the formula:

C(n,r)=n!r!(nr)!C(n, r) = \frac{n!}{r!(n-r)!}
  1. Calculate Factorials: Compute the factorials of nn, rr, and nrn-r, and simplify the expression.

  2. Find the Result: Perform the division to find the total number of combinations.


Worked Examples

infoNote

Example 1: Choosing Committee Members

Problem: A club has 1010 members.

How many ways can they choose a 33-member committee?


Solution:

Step 1: Identify n=10n=10 and r=3r=3


Step 2: Apply the formula:

C(10,3)=10!3!(103)!=10!3!×7!C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10!}{3! \times 7!}

Step 3: Simplify using factorials:

C(10,3)=10×9×83×2×1=7206=120C(10, 3) = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \frac{720}{6} = 120

Answer: There are 120 ways to choose the committee.


infoNote

Example 2: Selecting Students for a Group

Problem: A teacher has 1515 students and needs to select 55 for a project.

How many ways can this be done?


Solution:

Step 1: Identify n=15n=15 and r=5r=5


Step 2: Apply the formula:

C(15,5)=15!5!(155)!=15!5!×10!C(15, 5) = \frac{15!}{5!(15-5)!} = \frac{15!}{5! \times 10!}

Step 3: Simplify using factorials:

C(15,5)=15×14×13×12×115×4×3×2×1=360360120=3003C(15, 5) = \frac{15 \times 14 \times 13 \times 12 \times 11}{5 \times 4 \times 3 \times 2 \times 1} = \frac{360360}{120} = 3003

Answer: There are 3,003 ways to select the group.


Summary

  • Combination Formula:
C(n,r)=n!r!(nr)!C(n, r) = \frac{n!}{r!(n-r)!}
  • Order does not matter in combinations.
  • Factorials are key to computing combinations.
  • Applications include selecting groups, teams, or subsets where order is irrelevant.
Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master Combinations

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

40 flashcards

Flashcards on Combinations

Revise key concepts with interactive flashcards.

Try Mathematics Flashcards

4 quizzes

Quizzes on Combinations

Test your knowledge with fun and engaging quizzes.

Try Mathematics Quizzes

29 questions

Exam questions on Combinations

Boost your confidence with real exam questions.

Try Mathematics Questions

27 exams created

Exam Builder on Combinations

Create custom exams across topics for better practice!

Try Mathematics exam builder

322 papers

Past Papers on Combinations

Practice past papers to reinforce exam experience.

Try Mathematics Past Papers

Other Revision Notes related to Combinations you should explore

Discover More Revision Notes Related to Combinations to Deepen Your Understanding and Improve Your Mastery

96%

114 rated

Combinations

Combinations

user avatar
user avatar
user avatar
user avatar
user avatar

215+ studying

188KViews
Load more notes

Join 500,000+ Leaving Cert students using SimpleStudy...

Join Thousands of Leaving Cert Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered