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Cubic Sequences Simplified Revision Notes

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Cubic Sequences

Introduction

infoNote

A cubic sequence is a sequence of numbers where the third difference of every consecutive term is constant.

Consider a sequence of the first 77 cubed numbers :


image

The first difference of the sequence forms a quadratic sequence, the second difference forms a linear (arithmetic) sequence and the third difference is constant.

The general term of a cubic sequence is given by :

Tn=an3+bn2+cn+dT_n=an^3+bn^2+cn+d

A useful property of cubic sequence is that the third difference is given by :

6a6a

Example

infoNote

Find the general term, TnT_n of the following cubic sequence 1,13,51,125,247,...-1,13,51,125,247,...

First, identify the third common difference. Start by taking the first difference.

14,38,74,122,...14,38,74,122,...

Then the second difference :

24,36,48,...24,36,48,...

Finally, the third common difference :

12,12,...12,12,...

Apply the property of the n3n^3 coefficient, aa :

6a=12a=2\begin{align*} 6a&=12 \\ a&=2 \end{align*}

The general term looks like this at the moment :

Tn=2n3+bn2+cn+d\begin{align*} T_n=2n^3+bn^2+cn+d \end{align*}

Substitute some of the terms that known to form three equations in terms of b,c,db,c,d.

T1=1=2(1)3+b(1)2+c(1)+d=1=2+b+c+d=3=b+c+dT2=13=2(2)3+b(2)2+c(2)+d=13=16+4b+2c+d=3=4b+2c+dT3=51=2(3)3+b(3)2+c(3)+d=51=54+9b+3c+d=3=9b+3c+d\begin{align*} T_1 &=-1 &&=2(1)^3+b(1)^2+c(1)+d \\ &=-1 &&=2+b+c+d \\ &= -3 &&=b+c+d \\\\ T_2 &=13 &&=2(2)^3+b(2)^2+c(2)+d \\ &=13 &&=16+4b+2c+d \\ &= -3 &&=4b+2c+d \\\\ T_3 &=51 &&=2(3)^3+b(3)^2+c(3)+d \\ &=51 &&=54+9b+3c+d \\ &= -3 &&=9b+3c+d \\ \end{align*}

With three equations established, solve simultaneously. Refer to the simultaneous equations chapter.

b=0,c=0,d=3b=0,c=0,d=-3Tn=2n33\begin{align*} T_n=2n^3-3 \end{align*}
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