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Perpendicular Lines Simplified Revision Notes

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Perpendicular Lines

What Are Perpendicular Lines?

Two lines are perpendicular if they intersect to form a right angle (9090°). In coordinate geometry, the slopes of two perpendicular lines are related in the following way:

m1×m2=1m_1 \times m_2 = -1

where m1m_1 and m2m_2 are the slopes of the lines.

Equation of a Perpendicular Line

If you know the slope m1m_1 of one line, the slope m2m_2 of a line perpendicular to it is:

m2=1m1,m10m_2 = -\frac{1}{m_1}, \quad m_1 \neq 0

Special Cases:

  • A vertical line (x=kx = k) is perpendicular to a horizontal line (y=ky = k).
  • The slope of a vertical line is undefined, while the slope of a horizontal line is 00.

Finding a Perpendicular Line

To find the equation of a line perpendicular to a given line and passing through a specific point, use the point-slope form:

yy1=m(xx1)y - y_1 = m(x - x_1)

where mm is the slope of the perpendicular line and (x1,y1)(x_1, y_1) is the point through which the line passes.


Worked Examples

infoNote

Example 1: Verify Perpendicularity

Problem: Determine if the lines y=2x+1y = 2x + 1 and y=12x+3y = -\frac{1}{2}x + 3 are perpendicular.


Solution:

Step 1: Identify the slopes:

  • m1=2m_1 = 2
  • m2=12m_2 = -\frac{1}{2}

Step 2: Check the product of the slopes:

m1×m2=2×12=1m_1 \times m_2 = 2 \times -\frac{1}{2} = -1

Answer: Yes, the lines are perpendicular.


infoNote

Example 2: Find the Equation of a Perpendicular Line

Problem: Find the equation of a line perpendicular to y=3x+2y = -3x + 2 and passing through (4,1)(4,1)


Solution:

Step 1: Identify variables

The slope of the given line is m1=3m_1 = -3.

The slope of the perpendicular line is:

m2=1m1=13=13m_2 = -\frac{1}{m_1} = -\frac{1}{-3} = \frac{1}{3}

Step 2: Use the point-slope form:

yy1=m(xx1)y - y_1 = m(x - x_1)

Substitute m=13m = \frac{1}{3}, x1=4x_1 = 4, and y1=1y_1 = 1:

y1=13(x4)y - 1 = \frac{1}{3}(x - 4)

Step 3: Simplify:

y1=13x43y=13x43+1y - 1 = \frac{1}{3}x - \frac{4}{3} \quad \Rightarrow \quad y = \frac{1}{3}x - \frac{4}{3} + 1y=13x+23y = \frac{1}{3}x + \frac{2}{3}

Answer: The equation of the perpendicular line is y=13x+23y = \frac{1}{3}x + \frac{2}{3}


Summary

  • Definition: Perpendicular lines intersect to form a right angle.
  • Key Property: The slopes of two perpendicular lines satisfy m1×m2=1m_1 \times m_2 = -1
  • Special Cases: Vertical lines (x=kx = k) and horizontal lines (y=ky = k) are perpendicular.
  • To find the equation of a perpendicular line:
    1. Determine the negative reciprocal of the slope.
    2. Use the point-slope formula.
  • Practice identifying perpendicular lines and deriving their equations to strengthen understanding.
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