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Linear Simultaneous Equations Simplified Revision Notes

Revision notes with simplified explanations to understand Linear Simultaneous Equations quickly and effectively.

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Linear Simultaneous Equations

infoNote

Simultaneous linear equations are a set of two or more linear equations with multiple variables, solved together to find values of the variables that satisfy all equations simultaneously (at the same time)

Let's consider two linear equations :

  • x+2y=10x+2y=10
  • 3xy=53x-y=5 On a graph, the two linear equations look like this :

image

You'll notice that both lines share a single point, the point of intersection, this is the point that satisfies both line simultaneously.

There are two ways to solve simultaneous equations

  • Elimination
  • Substitution

Method 1 : Elimination


Example

infoNote

Solve the pair of simultaneous equations :

2x+3y=10(Equation A)5x4y=7(Equation B)2x + 3y = 10 \quad \text{(Equation A)} \\ 5x - 4y = 7 \quad \text{(Equation B)}

Eliminate one variable, we can multiply Equation A by 55

10x+15y=50(Equation A)10x + 15y = 50 \quad \text{(Equation A)}

Multiply Equation B by 22

10x8y=14(Equation B)10x - 8y = 14 \quad \text{(Equation B)}

Subtract the equations :

10x+15y=50(10x8y=14)23y=3610x + 15y = 50\quad \\ \underline{-(10x - 8y = 14)} \quad \\ 23y=36

Solve for yy :

y=3623\therefore \boxed {y = \frac{36}{23}}

Substitute y back into one of the original equations to find xx:

2x+3(3623)=102x + 3\left(\frac{36}{23}\right) = 102x=10108232x = 10 - \frac{108}{23}2x=122232x = \frac{122}{23}x=6123\therefore \boxed {x = \frac{61}{23}}

Method 2 : Substitution


Example

infoNote

Solve the pair of simultaneous equations :

2x+3y=10(Equation A)5x4y=7(Equation B)2x + 3y = 10 \quad \text{(Equation A)} \\ 5x - 4y = 7 \quad \text{(Equation B)}

Solve for one variable :

2x+3y=102x + 3y = 10 2x=103y2x = 10 - 3y x=103y2.x = \frac{10 - 3y}{2}.

Substitute into the other equation

5x4y=75x - 4y = 7 5(103y2)4y=75\left(\frac{10 - 3y}{2}\right) - 4y = 7

Simplify:

5(103y)24y=7\frac{5(10 - 3y)}{2} - 4y = 7 5015y24y=7\frac{50 - 15y}{2} - 4y = 7 5015y8y=1450 - 15y - 8y = 14 5023y=1450 - 23y = 14 23y=1450-23y = 14 - 50 23y=36-23y = -36 y=3623=3623.y = \frac{-36}{-23} = \frac{36}{23}.

Substitute Back to Solve for xx :

x=103y2x = \frac{10 - 3y}{2} x=103(3623)2x = \frac{10 - 3\left(\frac{36}{23}\right)}{2} x=12246.x = \frac{122}{46}. x=6123.x = \frac{61}{23}.
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