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A Deck of Cards Simplified Revision Notes

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A Deck of Cards

Overview

A standard deck of cards is commonly used in probability and combinatorics to illustrate concepts of counting and probability. It consists of 52 cards divided into suits and ranks.

Structure of a Deck

Suits:

  • 4 suits: Hearts (♥), Diamonds (♦), Clubs (♣), Spades (â™ ).
  • Hearts and Diamonds are red, Clubs and Spades are black.

Ranks:

13 ranks per suit: 2,3,4,…,10,Jack (J),Queen (Q),King (K),Ace (A)2, 3, 4, \dots, 10, \text{Jack (J)}, \text{Queen (Q)}, \text{King (K)}, \text{Ace (A)}

Special Groups:

  • Face Cards: Jack, Queen, King (3 per suit, 12 total).
  • Number Cards: 2 through 10
  • Aces: Often treated as high cards but can be low in certain games.

Applications in Probability

Equally Likely Outcomes:

  • Each card has an equal chance of being selected when shuffled properly.

Sample Space:

  • A single card draw has 52 possible outcomes.

Event Examples:

  • Probability of drawing a Heart:
P(Heart)=1352=14P(\text{Heart}) = \frac{13}{52} = \frac{1}{4}
  • Probability of a Face Card:
P(Face Card)=1252=313P(\text{Face Card}) = \frac{12}{52} = \frac{3}{13}

Worked Examples

infoNote

Example 1: Drawing a Red Card

Problem: What is the probability of drawing a red card?


Solution:

Step 1: Identify total red cards:

  • Hearts: 13, Diamonds: 13
  • Total red cards = 13 + 13 = 26

Step 2: Calculate probability:

P(Red Card)=2652=12P(\text{Red Card}) = \frac{26}{52} = \frac{1}{2}

Answer: The probability is 12\frac{1}{2} or 50%


infoNote

Example 2: Drawing an Ace or a King

Problem: What is the probability of drawing either an Ace or a King?


Solution:

Step 1: Count favourable outcomes:

  • Aces: 4 (one per suit).
  • Kings: 4 (one per suit).
  • Total = 4 + 4 = 8

Step 2: Calculate probability:

P(Ace or King)=852=213P(\text{Ace or King}) = \frac{8}{52} = \frac{2}{13}

Answer: The probability is 213\frac{2}{13}


infoNote

Example 3: Drawing a Heart or a Face Card

Problem: What is the probability of drawing a Heart or a Face Card?


Solution:

Step 1: Count total outcomes:

  • Hearts: 13
  • Face Cards: 12
  • Overlap (Face Cards in Hearts): 3
  • Total = 13 + 12 - 3 = 22

Step 2: Calculate probability:

P(Heart or Face Card)=2252=1126P(\text{Heart or Face Card}) = \frac{22}{52} = \frac{11}{26}

Answer: The probability is 1126\frac{11}{26}


Summary

  • A standard deck has:
    • 52 cards, divided into 4 suits and 13 ranks.
    • Red (Hearts/Diamonds) and Black (Clubs/Spades).
    • Face Cards (12 total) and Aces (4 total).
  • Useful for probability problems because each card is equally likely.
  • Probabilities can involve:
    • Individual suits, ranks, or combinations.
    • Events with overlaps require subtraction of the overlap to avoid double-counting.
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