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Definite Integrals Simplified Revision Notes

Revision notes with simplified explanations to understand Definite Integrals quickly and effectively.

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Definite Integrals

Definite integration is the process of calculating the exact area under a curve over a specific interval. Unlike indefinite integration, which results in a family of functions (antiderivatives) plus a constant of integration, definite integration yields a specific numerical value representing the net area under the curve.

1. The Definite Integral:

infoNote

The definite integral of a function f(x)f(x) from a to bb is denoted by: abf(x)dx\int_a^b f(x) \, dx This represents the net area under the curve y=f(x)y=f(x) from x=ax=a to x=bx=b

2. Interpreting the Definite Integral:

  • Area Under the Curve: If f(x)f(x) is positive over  [a,b]\ [a, b], the definite integral represents the area between the curve and the xx-axis from x=ax = a to x=b.x = b.
  • Net Area: If f(x)f(x) takes on both positive and negative values over  [a,b],\ [a, b], the definite integral gives the net area, with regions below the xx-axis subtracting from the total area.
  • Total Area: To find the total area regardless of whether the function is above or below the xx-axis, you would integrate the absolute value of the function.

3. Fundamental Theorem of Calculus:

infoNote

The Fundamental Theorem of Calculus connects differentiation and integration and provides a straightforward method to compute definite integrals: abf(x)dx=F(b)F(a) \int_a^b f(x) \, dx = F(b) - F(a) \\ where F(x)F(x) is an antiderivative of f(x)f(x) (i.e., F(x)=f(x)F'(x) = f(x)).

4. Steps to Compute a Definite Integral:

infoNote
  1. Find an Antiderivative F(x)F(x) off(x f(x): Determine the indefinite integral f(x)dx=F(x)+C.\int f(x) \, dx = F(x) + C.
  2. Evaluate the Antiderivative at the Limits: Compute F(b)F(a).F(b) - F(a).
  3. Interpret the Result: The result F(b)F(b) -F(a) F(a) gives the net area under the curve from x=ax = a to x=bx = b.

5. Examples of Definite Integration:

infoNote

Example 1: Basic Polynomial Function

Compute13(2x2+3x)dx. \int_1^3 (2x^2 + 3x) \, dx.

  • Step 1: Find the antiderivative: (2x2+3x)dx=2x33+3x22+C \int (2x^2 + 3x) \, dx = \frac{2x^3}{3} + \frac{3x^2}{2} + C \\ So, F(x)=2x33+3x22.F(x) = \frac{2x^3}{3} + \frac{3x^2}{2}.
  • Step 2: Evaluate at the limits: F(3)F(1)=(2(3)33+3(3)22)(2(1)33+3(1)22) F(3) - F(1) = \left(\frac{2(3)^3}{3} + \frac{3(3)^2}{2}\right) - \left(\frac{2(1)^3}{3} + \frac{3(1)^2}{2}\right) \\ F(3)=2(27)3+272=18+13.5=:highlight[31.5]F(3) = \frac{2(27)}{3} + \frac{27}{2} = 18 + 13.5 = :highlight[31.5]\\ F(1)=2(1)3+3(1)2=23+32=4+96=136:highlight[2.167]F(1) = \frac{2(1)}{3} + \frac{3(1)}{2} = \frac{2}{3} + \frac{3}{2} = \frac{4 + 9}{6} = \frac{13}{6} \approx :highlight[2.167]\\ Result: :success[31.52.16729.333]\text{Result: } :success[31.5 - 2.167 \approx 29.333]
infoNote

Example 2: Trigonometric Function

Compute 0π/2sin(x)dx.\int_0^{\pi/2} \sin(x) \, dx.

  • Step 1: Find the antiderivative: sin(x)dx=cos(x)+C \int \sin(x) \, dx = -\cos(x) + C \\ So, F(x)=cos(x).F(x) = -\cos(x).
  • Step 2: Evaluate at the limits: F(π2)F(0)=cos(π2)(cos(0))F\left(\frac{\pi}{2}\right) - F(0) = -\cos\left(\frac{\pi}{2}\right) - (-\cos(0))\\ F(π2)=cos(π2)=:highlight[0]F\left(\frac{\pi}{2}\right) = -\cos\left(\frac{\pi}{2}\right) = :highlight[0]\\ F(0)=cos(0)=:highlight[1]F(0) = -\cos(0) = :highlight[-1]\\ Result: :success[0(1)=1]\text{Result: } :success[0 - (-1) = 1]

6. Properties of Definite Integrals:

Definite integrals have several important properties that can simplify calculations:

  1. Linearity: ab[f(x)+g(x)]dx=abf(x)dx+abg(x)dx\int_a^b [f(x) + g(x)] \, dx = \int_a^b f(x) \, dx + \int_a^b g(x) \, dx abcf(x)dx=cabf(x)dx\int_a^b c \cdot f(x) \, dx = c \cdot \int_a^b f(x) \, dx where c is a constant.
  2. Reversing Limits: abf(x)dx=baf(x)dx\int_a^b f(x) \, dx = -\int_b^a f(x) \, dx
  3. Zero Integral: aaf(x)dx=:highlight[0]\int_a^a f(x) \, dx = :highlight[0]
  4. Additivity: abf(x)dx+bcf(x)dx=acf(x)dx\int_a^b f(x) \, dx + \int_b^c f(x) \, dx = \int_a^c f(x) \, dx

7. Applications of Definite Integrals:

  • Area under a Curve: The most common application, where the definite integral represents the area under the curve between two points.
  • Physics: Used to calculate quantities like displacement, work, and energy when integrating rates over time or other variables.
  • Economics: Used to find consumer and producer surplus, or to calculate total revenue or cost over a given interval.
  • Probability: Used in finding probabilities and expected values in continuous probability distributions.

Summary:

infoNote
  • Definite integration provides a way to calculate the exact area under a curve between two points, yielding a specific numerical result.
  • Definite integrals are widely used across mathematics, physics, economics, and many other fields to solve practical problems involving areas, accumulated quantities, and rates of change.

Definite Integral

13(x2+2x)dx\int_{1}^{3} (x^2 + 2x) dx

is an example of a definite integral. The two small numbers are called limits. The integral is described as "the integral between 33 and 11 of x2dxx^2 \quad dx."

Perform the integration, putting the answer in square brackets with limits:

[x33+2x22+c]13=[x33+x2+c]13\left[ \frac{x^3}{3} + \frac{2x^2}{2} +\xcancel c\right]_1^3 = \left[\frac{x^3}{3} + x^2+\xcancel c \right]_1^3

Sub in top limit and bottom limit for x and subtract:

((3)33+(3)2+c)((1)33+(1)2+c)\left( \frac{(3)^3}{3} + (3)^2+ \xcancel c \right) - \left( \frac{(1)^3}{3} + (1)^2+ \xcancel c \right)

Note: c's always cancel

Evaluate:

=:success[503]= :success[\frac{50}{3}] image
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