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Dividing Algebraic Expressions Simplified Revision Notes

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Dividing Algebraic Expressions

Division

Similar to multiplication, we handle respective components, divide coefficients and subtract exponents where applicable. We refer to the indices rules again :

xpxq=xpq\frac{x^p}{x^q}=x^{p-q}
infoNote

Division is synonymous with fractions, and using them interchangeably is key to understanding algebra, especially when dealing with fractions. When expressing division, we use fraction notation instead of ÷÷ or // .

A key property of fractions is that when the numerator and denominator share a common factor, it cancels out :

abac=abac=bc\frac{ab}{ac}=\frac{\cancel{a}b}{\cancel{a}c}=\frac{b}{c}
infoNote

aa must be a common factor of everything of the top and everything of the bottom of the fraction. A common mistake is to cancel out aa when this is not the case :

ab+dac=ab+dac=b+dc\frac{ab+d}{ac}=\frac{\cancel{a}b+d}{\cancel{a}c}=\frac{b+d}{c}

This is wrong.

Let's explore some examples :


4x22x=22xx2x=22xx2x=2x1=2x\frac{4x^2}{2x}=\frac{2 \cdot2 \cdot x \cdot x}{2 \cdot x}=\frac{\cancel{2} \cdot2 \cdot \cancel{x} \cdot x}{\cancel{2} \cdot \cancel{x}}=\frac{2x}{1}=2x

Recall we handle components separately, so the constants divide (4÷2=24÷2=2) and the xx-terms divide, using indices rules. Here's another way of looking at it :

4x22x=42x2x=2x21=2x\frac{4x^2}{2x}=\frac{4}{2} \cdot \frac{x^2}{x}=2\cdot x^{2-1}=2x
8b5a23b2=8b3a23\frac{8b^5a^2}{3b^2}=\frac{8b^3a^2}{3}

88 and 33 don't divide evenly so we can leave those untouched if we want to avoid decimal notation. The bb-terms are handled using indices rules and the aa term doesn't have anything to cancel out with on the bottom of the fraction, so this stays unaffected. Here's a more exhaustive solution :

8b5a23b2=83b5b2a21=83b52a2=8b3a23\frac{8b^5a^2}{3b^2}=\frac{8}{3} \cdot \frac{b^5}{b^2} \cdot \frac{a^2}{1}=\frac{8}{3} \cdot b^{5-2} \cdot a^2=\frac{8b^3a^2}{3}

In many cases, expressions may need to be factored so we can identify common factors on the denominator and numerator.

Example

infoNote

Simplify :

x325xx5\frac{x^3-25x}{x-5}

The denominator is in its simplest form, the numerator can be factored, notice a common factor of xx.

x(x225)x5\frac{x(x^2-25)}{x-5}

Nothing cancels out yet, however, within the brackets, we have a difference of two squares.

x(x5)(x+5)x5\frac{x(x-5)(x+5)}{x-5}

Now both the numerator and denominator have a common factor :

x(x5)(x+5)x5\frac{x\cancel{(x-5)}(x+5)}{\cancel{x-5}}x(x+5)1=x(x+5)\frac{x(x+5)}{1}=x(x+5)
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