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6.1 Explain why: 6.1.1 Depreciation and bad debts will not appear in a Cash Budget - NSC Accounting - Question 6 - 2017 - Paper 1

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6.1 Explain why: 6.1.1 Depreciation and bad debts will not appear in a Cash Budget. Any valid explanation: - Depreciation represents a non-cash expense, reflecting... show full transcript

Worked Solution & Example Answer:6.1 Explain why: 6.1.1 Depreciation and bad debts will not appear in a Cash Budget - NSC Accounting - Question 6 - 2017 - Paper 1

Step 1

6.2.1 Complete the Debtors Collection Schedule.

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Answer

MONTH CREDIT SALES NOVEMBER DECEMBER September 180 000 32 400 ? October 186 000 55 800 33 480 November ? 92 225 198 400 December 210 000 ? 42 000 TOTAL ? ?

Step 2

6.2.2 (i) Cash sales for December:

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Answer

To calculate Cash Sales for December, we use the formula:

[ \text{Cash Sales} = \text{Credit Sales} \times \frac{40}{100} ]

For December: [ 210,000 \times \frac{40}{100} = 140,000 ]

Thus, Cash sales for December is R140 000.

Step 3

6.2.2 (ii) Rent income amount for November:

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Answer

To calculate the Rent Income amount for November, we use the formula:

[ \text{Rent Income} = \text{Increase} \times \frac{100}{8} ]

Using the given increase of 8%: [ 19,710 \times \frac{100}{100} = 18,250 ]

Thus, Rent income for November is R18,250.

Step 4

6.2.2 (iii) Payments to creditors for November:

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Answer

To calculate Payments to Creditors for November, we use the following calculation:

[ \text{Cash Purchases of Stock} = \text{Credit Sales} \times \frac{100}{60} ] Using the values: [ 186,000 \times \frac{100}{100} = 310,000] Thus, Payments to creditors for November is R198,400.

Step 5

6.2.2 (iv) Salaries and wages for November:

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Answer

As given, Salaries and wages in November would remain the same:

[ 86,000 - 35,600 = 35,600] Thus, Salaries and wages in November is R109,400.

Step 6

6.2.2 (v) Loan instalment (including interest) for December:

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Answer

To calculate Loan instalment (including interest) for December:

[ 13,625 - 1,625 + (150,000 - 12,000) \times 13% \times \frac{1}{12} ] Using the values: [ 12,000 + 1,495 = 13,495] Thus, Loan instalment for December is R13,495.

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