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4.1 Below are photographs of fasteners that are used on building sites - NSC Civil Technology Civil Services - Question 4 - 2017 - Paper 1

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4.1 Below are photographs of fasteners that are used on building sites. Write down the name and ONE use of EACH fastener next to the question number (4.1.1–4.1.3) i... show full transcript

Worked Solution & Example Answer:4.1 Below are photographs of fasteners that are used on building sites - NSC Civil Technology Civil Services - Question 4 - 2017 - Paper 1

Step 1

4.2 Name ONE fastener that you will use when joining purlins to rafters.

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Answer

One suitable fastener for joining purlins to rafters is a steel cut nail. This type of nail is primarily used to fix skirting and cleats to brickwork.

Step 2

4.3 State TWO advantages of nails over screws.

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Answer

  1. Nails are quicker to drive in than screws, making them more efficient for fastening.

  2. Unlike screws, nails can be made of rust-proof materials, such as copper or stainless steel, which enhances their durability and lifespan.

Step 3

4.4 Name ONE pipe that can be joined by means of a compression joint.

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Answer

A copper pipe can be joined using a compression joint.

Step 4

4.6.1 Calculate the inside area of the room in square metres (m²). Round off your answer to TWO decimal places.

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Answer

To find the inside area of the room, we first calculate the inside measurements:

  • Long walls: 7,000 mm2×220 mm=6,560 mm7,000 \text{ mm} - 2 \times 220 \text{ mm} = 6,560 \text{ mm}
  • Short walls: 4,000 mm2×220 mm=3,560 mm4,000 \text{ mm} - 2 \times 220 \text{ mm} = 3,560 \text{ mm}

Convert measurements to metres:

  • Long walls: 6,560 mm=6.56 m6,560 \text{ mm} = 6.56 \text{ m}
  • Short walls: 3,560 mm=3.56 m3,560 \text{ mm} = 3.56 \text{ m}

Calculate area:

Area=Length×Width=6.56 m×3.56 m=23.36 m2\text{Area} = \text{Length} \times \text{Width} = 6.56 \text{ m} \times 3.56 \text{ m} = 23.36 \text{ m}^2

Step 5

4.6.2 Calculate the area of ONE ceiling board in square metres (m²).

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Answer

The area of one ceiling board can be calculated as follows:

Area=Length×Width=4,200 mm×1,200 mm\text{Area} = \text{Length} \times \text{Width} = 4,200 \text{ mm} \times 1,200 \text{ mm}

Converting to metres:

Area=4.2 m×1.2 m=5.04 m2\text{Area} = 4.2 \text{ m} \times 1.2 \text{ m} = 5.04 \text{ m}^2

Step 6

4.6.3 Calculate the length of the skirting required in metres (m). Ignore the reveals.

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Answer

The length of skirting can be calculated by summing the lengths of all walls:

  • Total length: (6,560extmm+3,560extmm)×2ext(forbothsides)3,000extmm(door)(6,560 ext{ mm} + 3,560 ext{ mm}) \times 2 ext{ (for both sides)} - 3,000 ext{ mm (door)}

=(20,240extmm3,000extmm)=17,240extmm= (20,240 ext{ mm} - 3,000 ext{ mm}) = 17,240 ext{ mm}

Convert to metres:

17,240extmm=17.24extm17,240 ext{ mm} = 17.24 ext{ m}

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