3.1 State the difference between a monostable multivibrator and an astable multivibrator with reference to their output states - NSC Electrical Technology Digital - Question 3 - 2022 - Paper 1
Question 3
3.1 State the difference between a monostable multivibrator and an astable multivibrator with reference to their output states.
3.2 FIGURE 3.2 shows a bistable mult... show full transcript
Worked Solution & Example Answer:3.1 State the difference between a monostable multivibrator and an astable multivibrator with reference to their output states - NSC Electrical Technology Digital - Question 3 - 2022 - Paper 1
Step 1
State the difference between a monostable multivibrator and an astable multivibrator with reference to their output states.
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Answer
A monostable multivibrator has only one stable state, which means it transitions briefly to its unstable state upon receiving a trigger and then returns to the stable state. An astable multivibrator, on the other hand, does not have a stable state; it continuously toggles between its high and low states, generating a square wave output.
Step 2
State the purpose of C2 and R3.
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C2 and R3 in the circuit serve to define the time period for which the output remains in its altered state prior to returning to its stable configuration. C2 charges and discharges through R3, which determines the duration of the output pulse.
Step 3
Determine the voltage at the non-inverting input (Vb) when capacitor C2 is fully charged to the saturation voltage of 9 V and no current flows through R3.
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When capacitor C2 is fully charged to its saturation voltage of 9 V, the voltage at the non-inverting input (Vb) will be 0 V, as the charge does not allow current to flow through R3, thus keeping the inverting input at a reference voltage.
Step 4
Explain what happens to the output voltage the moment a positive input pulse is applied to the inverting input.
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Upon application of a positive input pulse at the inverting input, the output voltage transitions from a positive saturation level (9 V) to negative saturation (-9 V). This is due to the comparator action within the circuit, responding to the changes in voltage levels at its inputs.
Step 5
Draw the output waveform on the ANSWER SHEET for question 3.3.4.
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The output waveform should reflect the changes corresponding to the input pulse being applied to the inverting input. It will represent variations that correspond to high and low states based on the timing set by C2 and R3.
Step 6
Determine the polarity of Vb when the output is positive.
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When the output is positive, the polarity of Vb is also positive, as it receives a high voltage relative to the reference point.
Step 7
Refer to Va and Vb and state when the output changes from +9 V to −9 V.
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The output changes from +9 V to -9 V when the voltage Va becomes higher than Vb, which triggers the transition of the output state.
Step 8
Describe how an increase in the value of RF affects the operation of the circuit.
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Increasing the value of RF will increase the timing constant of the circuit, as it will result in a slower charge and discharge rate for the capacitor, thereby altering the frequency of the output signal and possibly reducing the overall frequency.
Step 9
Determine the saturation voltages of the Schmitt trigger.
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The saturation voltages for the Schmitt trigger typically are +9 V and -9 V, which indicate the levels between which the output will transition.
Step 10
Explain the purpose of RF and R1 in the circuit.
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RF and R1 are used to set the reference voltage at the non-inverting input of the operational amplifier in the Schmitt trigger configuration. These resistors help determine the trigger voltages that dictate when the output changes state.