Photo AI

2.1 Name the instrument that is used to measure electrical energy - NSC Electrical Technology Electronics - Question 2 - 2016 - Paper 1

Question icon

Question 2

2.1-Name-the-instrument-that-is-used-to-measure-electrical-energy-NSC Electrical Technology Electronics-Question 2-2016-Paper 1.png

2.1 Name the instrument that is used to measure electrical energy. 2.2 State TWO advantages of three-phase systems over single-phase systems. 2.3 Draw a neatly lab... show full transcript

Worked Solution & Example Answer:2.1 Name the instrument that is used to measure electrical energy - NSC Electrical Technology Electronics - Question 2 - 2016 - Paper 1

Step 1

Name the instrument that is used to measure electrical energy.

96%

114 rated

Answer

The instrument used to measure electrical energy is an Energy Meter, commonly referred to as a Watt-hour meter.

Step 2

State TWO advantages of three-phase systems over single-phase systems.

99%

104 rated

Answer

  1. Higher Efficiency: Three-phase systems can transmit more power over the same conductor size compared to single-phase systems, minimizing power losses.

  2. Smoother Power Delivery: Three-phase systems provide a more constant voltage and power supply, which reduces vibrations in motors and improves overall performance.

Step 3

Draw a neatly labelled sketch representing the voltage waveforms of a three-phase AC generation system.

96%

101 rated

Answer

The sketch should illustrate three sinusoidal waveforms, each 120 degrees apart. The y-axis represents voltage, and the x-axis represents time. Each waveform should be labeled as Phase A, Phase B, and Phase C, with their respective peaks and troughs clearly marked.

Step 4

Line voltage

98%

120 rated

Answer

To calculate the line voltage in a star-connected system, we use the formula:

V_L = rac{S}{ rac{ ext{sqrt}(3)}{I_L}}

Substituting in the values:

V_L = rac{20,000 ext{ VA}}{ rac{ ext{sqrt}(3)}{25 ext{ A}}}

Calculating gives:

VL=267.67extVV_L = 267.67 ext{ V}

Step 5

Phase voltage

97%

117 rated

Answer

Phase voltage in a star-connected system is given by:

V_P = rac{V_L}{ ext{sqrt}(3)}

Substituting in the previously calculated line voltage:

V_P = rac{267.67 ext{ V}}{ ext{sqrt}(3)}

This results in:

VP=154.78extVV_P = 154.78 ext{ V}

Step 6

Total input power

97%

121 rated

Answer

The total input power in a two-wattmeter system is calculated as:

PT=P1+P2P_T = P_1 + P_2

Substituting the given values:

PT=8extkW+4extkW=12extkWP_T = 8 ext{ kW} + 4 ext{ kW} = 12 ext{ kW}

Step 7

Line output power

96%

114 rated

Answer

The line output power can be calculated using the formula:

Pout=PTimesextpfP_{out} = P_T imes ext{pf}

With the power factor of 0.8, we find:

Pout=12extkWimes0.8=9.6extkWP_{out} = 12 ext{ kW} imes 0.8 = 9.6 ext{ kW}

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;