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4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET) - NSC Electrical Technology Electronics - Question 4 - 2021 - Paper 1

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4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET). 4.2 Refer to FIGURE 4.2 below and answer the questions that follow... show full transcript

Worked Solution & Example Answer:4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET) - NSC Electrical Technology Electronics - Question 4 - 2021 - Paper 1

Step 1

4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET).

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Answer

Enhancement Mode MOSFET.

Step 2

4.2.1 Identify the semiconductor symbol in FIGURE 4.2.

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Answer

The semiconductor symbol in FIGURE 4.2 is that of a MOSFET, specifically a P-channel enhancement mode.

Step 3

4.2.2 Explain how the metal-oxide-semiconductor field-effect transistor (MOSFET) differs from the junction field-effect transistor (JFET) with reference to its construction.

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Answer

The MOSFET has a metal-oxide layer that provides insulation between the gate electrode and the channel, while in a JFET, the gate and the channel are physically connected.

Step 4

4.3.1 Identify pulses B2.

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Pulses B2 are Sawtooth pulses.

Step 5

4.3.2 Explain the term saturation region with reference to the operation of the UJT.

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Answer

The saturation region occurs when the operating point has fallen beyond the valley point, and the emitter has been supplied with sufficient current.

Step 6

4.3.3 Describe how the UJT is driven into the CUT-OFF mode.

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The UJT is driven into the cut-off mode when the voltage across the capacitor falls to the UJT's emitter-base junction, consequently resetting the conditions.

Step 7

4.3.4 Draw the output voltage waveform across R2 on the ANSWER SHEET for QUESTION 4.3.4.

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A sketch of the output voltage waveform across R2 should reflect the behavior of the UJT circuit, showing the transition between cut-off and saturation.

Step 8

4.4.1 Identify the circuit diagram in FIGURE 4.4.

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Answer

The circuit diagram in FIGURE 4.4 is a Darlington transistor amplifier.

Step 9

4.4.2 Describe how the transistors are biased and fully turned ON by referring to the required voltages.

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Answer

To fully turn on the transistors, a supply voltage exceeding 1.4 V is connected to the base of the Darlington transistor, ensuring sufficient biasing of both the base-emitter and collector-emitter junctions.

Step 10

4.4.3 State TWO advantages of the circuit in FIGURE 4.4.

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  1. It can supply high current gain.
  2. It has improved input impedance, reducing load on the preceding stages.

Step 11

4.4.4 Explain why the transistor in FIGURE 4.4 is preferred over a single transistor when used as a switch.

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A Darlington transistor is preferred because it can energize and operate switching devices that demand higher current.

Step 12

4.5.1 Identify the type of operational amplifier in FIGURE 4.5.

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Answer

The operational amplifier in FIGURE 4.5 is a Non-Inverting Operational Amplifier.

Step 13

4.5.2 Draw the output voltage waveform on the ANSWER SHEET for QUESTION 4.5.2.

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The output waveform should show the amplified response with a phase shift of zero from the input signal.

Step 14

4.5.3 Explain why operational amplifiers are known as differential voltage amplifiers.

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Answer

Operational amplifiers amplify the difference in voltage between two input signals, which makes them effective as differential amplifiers.

Step 15

4.6.1 Explain the function of the RS flip-flop.

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Answer

The RS flip-flop stores the last received information until new information is provided by its two stable states.

Step 16

4.6.2 State the typical operating voltage range of the 555 IC.

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Answer

+5 V to (+15 V or +18 V).

Step 17

4.6.3 Name TWO modes of operation for the 555 IC.

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Answer

  1. Astable Mode
  2. Monostable Mode.

Step 18

4.6.5 Explain the function of the threshold input on Pin 6 of 555 Timer IC.

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Answer

The threshold input monitors the voltage at which a 555 IC will reset when the voltage exceeds rac{1}{3} V_{CC}.

Step 19

4.7 Refer to FIGURE 4.7 below and explain why the output is zero volts.

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The output of the 741 Op-Amp is zero volts due to equal amplitudes at both inputs, causing cancellation.

Step 20

4.8.1 Calculate the output voltage.

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Given the values, the output voltage can be calculated using the formula: Vout=Vin(1+RfRn)V_{out} = V_{in} \left(1 + \frac{R_f}{R_n}\right) Substituting, we find: Vout=2.5mV(1+1102.2)=127.5mVV_{out} = 2.5 mV \left(1 + \frac{110}{2.2}\right) = 127.5 mV.

Step 21

4.8.2 Explain the effect on the output when the value of the feedback resistor is equal to that of the input resistor.

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Answer

When the feedback resistor is equal to the input resistor, the output voltage will be twice that of the input voltage.

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