Refer to FIGURE 4.1 below of an inverting operational amplifier and answer the questions that follow - NSC Electrical Technology Electronics - Question 4 - 2023 - Paper 1
Question 4
Refer to FIGURE 4.1 below of an inverting operational amplifier and answer the questions that follow.
4.1.1 State the purpose of the feedback resistor (R_f).
4.1.2... show full transcript
Worked Solution & Example Answer:Refer to FIGURE 4.1 below of an inverting operational amplifier and answer the questions that follow - NSC Electrical Technology Electronics - Question 4 - 2023 - Paper 1
Step 1
4.1.1 State the purpose of the feedback resistor (R_f).
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Answer
The feedback resistor (R_f) in an inverting operational amplifier is used to control the gain of the amplifier, ensuring it operates within the desired range. It provides a portion of the output voltage back to the input, which stabilizes the overall performance of the circuit.
Step 2
4.1.2 Explain why op amps are seldom used in open-loop mode.
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Op amps are rarely used in open-loop mode because their gain is extremely high, typically exceeding 100,000. This results in a very small input voltage creating a large output, making the system highly sensitive to noise and distortion, leading to instability and non-linear operation.
Step 3
4.1.3 Calculate the voltage gain of the circuit.
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To calculate the voltage gain (A_v) of the inverting operational amplifier, the formula is given by:
Av=−RinRf
Substituting the values:
Rf=1.2kΩ
Rin=1kΩ
Av=−1×1031.2×103=−1.2
Thus, the voltage gain of the circuit is -1.2.
Step 4
4.2.1 State TWO functions of resistor R_b in FIGURE 4.2.
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Resistor R_b sets the biasing point of the non-inverting input, allowing for stable operation of the amplifier.
It also assists in defining the input impedance of the circuit, impacting how the amplifier responds to varying signal conditions.
Step 5
4.2.2 Calculate the voltage gain of the circuit in FIGURE 4.2.
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The voltage gain (A_v) for a non-inverting amplifier can be calculated using:
Av=1+RinRf
Given:
Rf=120kΩ
Rin=10kΩ
Substituting these values:
Av=1+10×103120×103=1+12=13
Therefore, the voltage gain of the circuit is 13.
Step 6
4.3.1 Name TWO applications of the 555 IC.
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The 555 IC is commonly used in timer applications to create precise time delays.
It can also be utilized in pulse width modulation circuits for motor control.
Step 7
4.3.2 State TWO disadvantages of the 555 IC.
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The 555 IC has limited frequency response, making it unsuitable for high-speed applications.
It can consume more power compared to other modern timer circuits, affecting battery-operated designs.
Step 8
4.3.3 Describe the function of pin 4.
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Pin 4 of the 555 IC is the Reset pin, which is used to terminate the timing cycle. It allows external interrupts to function, resetting the timer even if it is currently active.
Step 9
4.3.4 State the functions of the following components in FIGURE 4.3 above: (a) NPN transistor.
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(a) The NPN transistor in the 555 circuit acts as a switch to control higher current loads based on the output signal from the timer. It allows external devices to be turned on or off at the specified timer interval.
Step 10
4.3.4 State the functions of the following components in FIGURE 4.3 above: (b) Comparator 2.
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(b) Comparator 2 in the 555 IC configuration is used to compare the input voltage against a reference level, enabling the detection of voltage thresholds necessary for starting or stopping the timing operation.