5.1 State ONE effect of switch bounce in electronic circuits - NSC Electrical Technology Electronics - Question 5 - 2024 - Paper 1
Question 5
5.1 State ONE effect of switch bounce in electronic circuits.
5.2 FIGURE 5.2 below shows the basic circuit diagram of an op-amp bistable multivibrator with its inpu... show full transcript
Worked Solution & Example Answer:5.1 State ONE effect of switch bounce in electronic circuits - NSC Electrical Technology Electronics - Question 5 - 2024 - Paper 1
Step 1
5.1 State ONE effect of switch bounce in electronic circuits.
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Answer
One effect of switch bounce is that it can produce multiple unwanted pulses when the switch transitions from open to closed or vice versa. This may be interpreted as multiple signals by the circuit, leading to incorrect operation.
Step 2
5.2.1 Explain feedback with reference to the circuit.
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Feedback in this circuit refers to a portion of the output voltage being fed back to the non-inverting input via the voltage divider formed by resistors R2 and R3. This ensures that the circuit maintains its state by comparing the input voltage against this feedback voltage.
Step 3
5.2.2 Explain how the capacitor reacts when a positive trigger pulse is applied to the input of the circuit.
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When a positive trigger pulse is applied, the capacitor C1 charges immediately to the applied voltage. This rapid charging influences the state of the op-amp, ultimately determining the output voltage level.
Step 4
5.2.3 Describe the operation of the circuit when a negative trigger pulse is applied.
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Upon receiving a negative trigger pulse, the op-amp compares the voltage levels at both of its inputs. If the voltage at the inverting input exceeds that at the non-inverting input, the output will transition to its low state, depending on the current configuration of feedback and input voltages.
Step 5
5.2.4 State when the output does not change when trigger pulse 2 is applied.
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The output does not change when trigger pulse 2 is applied if the voltage on the non-inverting input remains higher than the voltage on the inverting input, which keeps the circuit in its current state.
Step 6
5.3.1 Identify the multivibrator circuit in FIGURE 5.3.
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The circuit depicted in FIGURE 5.3 is a monostable multivibrator.
Step 7
5.3.2 State the function of resistor R2 in this circuit.
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Resistor R2 keeps pin 2 of the monostable circuit in its steady state by providing a defined reference voltage, which influences the timing and response of the circuit.
Step 8
5.3.3 Draw the output of the circuit for the given input on the ANSWER SHEET for QUESTION 5.3.3.
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The output waveform should reflect a single pulse corresponding to the duration defined by the timing components of the circuit when it receives a trigger signal.
Step 9
5.3.4 Determine the voltage at which the circuit will reset to its resting state. Give a reason for the answer.
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The voltage at which the circuit will reset to its resting state is 6 V because the voltage across the timing capacitor must charge up to two-thirds of the supply voltage before the output can return to its dormant state.
Step 10
5.4.1 Explain why the output of the circuit changes state continually.
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The output changes state continuously because both trigger pin 2 and threshold pin 6 are wired to the timing capacitor. As the capacitor charges and discharges, it causes the circuit to repeatedly reset and trigger, resulting in a continuous stream of high and low outputs.
Step 11
5.4.2 Explain why t1 and t2 are not equal.
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t1 and t2 are not equal because the capacitor charges through R1 but discharges through R2, causing differences in duration for the charging and discharging phases due to differing resistances.
Step 12
5.4.3 Calculate the frequency of the output.
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The frequency of the output can be calculated using the formula:
f = rac{1}{T}, where T is the total period. For the given values, substituting leads to a frequency of approximately 7.18 Hz.
Step 13
5.5.1 Determine the value of the reference voltage.
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The reference voltage can be determined by the voltage divider formed; it is calculated to be 4.5 V.
Step 14
5.5.2 Determine the resistance of R1. Motivate your answer.
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The resistance of R1 is significantly impacted by the feedback operation. Increasing its value will increase the voltage across R2, while maintaining the reference conditions of the comparator when applied.
Step 15
5.5.3 Draw the output voltage for the given input on the ANSWER SHEET for QUESTION 5.5.3.
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The output voltage will switch between +9 V and -9 V depending on whether the input voltage exceeds or falls below the reference voltage.
Step 16
5.5.4 Explain how an increase in the value of R1 will affect the voltage across R2.
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An increase in the value of R1 will mean that R1 > R2, resulting in a reduced voltage across R2 because the effective resistance seen by the voltage divider lowers the voltage drop across R2.
Step 17
5.6.1 Explain the purpose of a summing amplifier.
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A summing amplifier allows multiple input voltages to be combined and produces a single output voltage that represents the sum of its inputs, facilitating additive signal processing.
Step 18
5.6.2 Calculate the output voltage if Rf is set to 33 kΩ.
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Using the formula:
V_{out} = -rac{R_f}{R_1} V_1 - rac{R_f}{R_2} V_2 - rac{R_f}{R_3} V_3
Substituting leads to:
V_{out} = -rac{33000}{2200} (0.1) - rac{33000}{2200} (0.2) - rac{33000}{2200} (0.3) o V_{out} = -9 ext{V}.
Step 19
5.6.3 State why the output falls to 0.6 V when Rf is set to 220 Ω.
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When Rf is set to 220 Ω, the gain of the amplifier becomes 1, meaning the output voltage becomes equal to the sum of the input voltages, limited under the given conditions.
Step 20
5.7.1 Draw the output of the circuit for the given input on the ANSWER SHEET for QUESTION 5.7.1.
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The output should display a waveform that shows the charging and discharging of the capacitor corresponding to the input square wave.
Step 21
5.7.2 Explain the operation of the circuit during the first positive square wave.
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During the first positive square wave, both plates of the capacitor quickly charge to the potential of the input, maintaining that voltage as long as the input remains high.
Step 22
5.7.3 Illustrate, by means of a basic circuit diagram, how the circuit above can be changed into a passive integrator.
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To convert the circuit to a passive integrator, you would replace the capacitor with a resistor in series with the input signal and adjust the feedback loop accordingly, allowing for integral behavior of the input waveforms.