6.1 Describe the term stabilization with reference to amplifiers - NSC Electrical Technology Electronics - Question 6 - 2024 - Paper 1
Question 6
6.1 Describe the term stabilization with reference to amplifiers.
6.2 State ONE disadvantage of class AB push-pull amplifiers.
6.3 Refer to FIGURE 6.3 and answer t... show full transcript
Worked Solution & Example Answer:6.1 Describe the term stabilization with reference to amplifiers - NSC Electrical Technology Electronics - Question 6 - 2024 - Paper 1
Step 1
Describe the term stabilization with reference to amplifiers.
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Answer
Stabilization refers to the process of making the operating point of the transistor independent of variations in temperature and other parameters. This ensures that the amplifier continues to function effectively under varying conditions without unintended changes to the output.
Step 2
State ONE disadvantage of class AB push-pull amplifiers.
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Answer
One disadvantage of class AB push-pull amplifiers is that they tend to produce cross-over distortion when switching between the two transistors.
Step 3
Determine the quiescent collector current. If the base current is 20 µA.
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To determine the quiescent collector current (Ic), we can use the formula: I_C = eta imes I_B
Assuming a beta (β) value of 200, the quiescent collector current would be: IC=200imes20imes10−6=4extmA.
Step 4
Determine the quiescent voltage.
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The quiescent voltage (Vce) across the transistor can typically be determined from the DC load line. Given standard configurations, the voltage is often found to be around 10V depending on load conditions and supply voltage.
Step 5
Name TWO undesirable effects of incorrect biasing of the transistor in FIGURE 6.3 above.
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Two undesirable effects of incorrect biasing include:
Distortion of the output signal due to improper operation in the active region.
Potential damage to the transistor from thermal runaway, leading to failure.
Step 6
Name ONE disadvantage of the RC-coupled amplifier.
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One disadvantage of the RC-coupled amplifier is that it is unsuitable for low-frequency applications due to its frequency response characteristics.
Step 7
Briefly describe the effect when the temperature of a transistor increases beyond its normal operating point.
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When the temperature of a transistor exceeds its normal operating point, increased leakage current may flow, potentially leading to thermal runaway and destruction of the transistor.
Step 8
Explain why the RC-coupled amplifier can be regarded as a low-frequency filter.
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The RC-coupled amplifier blocks DC signals while allowing AC signals to pass. It exhibits a frequency response that diminishes effectively at lower frequencies, thus functioning as a low-frequency filter.
Step 9
State ONE disadvantage of the amplifier in FIGURE 6.5 above, relates the cost and the size of the transformer.
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A disadvantage of the amplifier is that it often requires a larger and more expensive transformer, impacting the overall cost and spatial efficiency of the design.
Step 10
State the importance of the impedance matching transformer in FIGURE 6.5 above.
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The impedance matching transformer maximizes power transfer by ensuring that the output impedance of the amplifier matches the load impedance (e.g., a speaker), enhancing performance.
Step 11
State TWO functions of capacitor C1.
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Two functions of capacitor C1 include:
Allowing AC signals to pass through while blocking DC signals.
Providing coupling between stages of amplification, maintaining signal integrity.
Step 12
Explain why the output waveform in FIGURE 6.5 is inverted and amplified.
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The output waveform is inverted because the transistor is configured in common-emitter mode, where the phase of the output is opposite to that of the input, and it is amplified due to the gain characteristics of the transistor.
Step 13
Name ONE advantage of the amplifier in FIGURE 6.6 above.
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One advantage of the push-pull amplifier is its efficiency, as it can produce a larger output signal compared to a Class A amplifier while minimizing distortion.
Step 14
State how cross-over distortion can be eliminated during the operation of the circuit in FIGURE 6.6 above.
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Cross-over distortion can be minimized by biasing both transistors slightly into conduction, ensuring that neither transistor is completely off during the transition, which helps in maintaining linearity.
Step 15
Describe the operation of the circuit during the negative half cycle of the input signal.
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During the negative half cycle, one transistor (Q2) conducts while the other (Q1) turns off, allowing the load to be driven by the active transistor, providing a discharge path and maintaining the output waveform.
Step 16
Identify the amplifier circuit from which the frequency response curve in FIGURE 6.7 above is derived.
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The frequency response curve is derived from a radio-frequency amplifier circuit, which typically exhibits a particular gain characteristic across a range of frequencies.
Step 17
Explain the term bandwidth? Filter with reference to the frequency response curve in FIGURE 6.7 above.
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Bandwidth refers to the range of frequencies over which the amplifier operates effectively. The frequency response curve illustrates how gain decreases beyond the designated lower (f1) and upper (f2) frequency limits, creating a filter effect.
Step 18
Briefly describe how resonant frequency can be changed.
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Resonant frequency can be modified by changing the values of the inductor or capacitor in the tank circuit; altering either component's value effectively shifts the resonant frequency.
Step 19
Name ONE application of the Colpitts oscillator.
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One application of the Colpitts oscillator is in radio transmitters and receivers for generating stable oscillatory signals.
Step 20
State the purpose of the tank circuit in FIGURE 6.8 above.
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The tank circuit serves to determine the frequency of oscillations within the oscillator circuit, acting as a resonant circuit.
Step 21
Calculate the oscillating frequency of the circuit in FIGURE 6.8 above when the total capacitance of the tank circuit is 150 µF and the value of the inductor is 200 mH.
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The oscillating frequency (f0) can be calculated using the formula: f_0 = rac{1}{2 ext{π} ext{√(LC)}}
Substituting the given values:
f_0 = rac{1}{2 ext{π} ext{√(200 imes 10^{-3} imes 150 imes 10^{-6})}} \\ = 29.06 ext{ Hz}.
Step 22
State the type of feedback used in FIGURE 6.9 above.
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The feedback used in this configuration is positive feedback, which reinforces the initial input signal.
Step 23
Explain the value of the phase shift each RC combination produces.
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Each RC combination produces a phase shift of 60°, contributing to the overall phase shift needed for the oscillation to occur.
Step 24
Calculate the frequency of oscillation if R1 = R2 = R3 = 10 kΩ and C1 = C2 = C3 = 0.001 µF.
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The frequency of oscillation (f0) can be calculated using: f_0 = rac{1}{2 ext{π}R ext{C}}
where R = R1 + R2 + R3 and C = C1 + C2 + C3:
f_0 = rac{1}{2 ext{π}(3 imes 10^4)(3 imes 10^{-9})} \\ = 20.54 ext{ Hz}.
Step 25
Explain the term attenuation.
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Attenuation is a reduction in signal strength. It occurs when the output voltage becomes smaller than the input voltage, often due to losses in the circuit components.