6.1 Describe the term stabilization with reference to amplifiers - NSC Electrical Technology Electronics - Question 6 - 2024 - Paper 1
Question 6
6.1 Describe the term stabilization with reference to amplifiers.
6.2 State ONE advantage of class AB push-pull amplifiers.
6.3 Refer to FIGURE 6.3 and answer the ... show full transcript
Worked Solution & Example Answer:6.1 Describe the term stabilization with reference to amplifiers - NSC Electrical Technology Electronics - Question 6 - 2024 - Paper 1
Step 1
Describe the term stabilization with reference to amplifiers.
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Answer
Stabilization is the process of making the operating point of the transistor independent of variations in its parameters due to changes in temperature. This is achieved through negative feedback mechanisms that adjust the biasing conditions, ensuring consistent performance under varying operational conditions.
Step 2
State ONE advantage of class AB push-pull amplifiers.
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Answer
One advantage of class AB push-pull amplifiers is that they effectively reduce cross-over distortion, enabling better linearity and improved sound quality in audio applications.
Step 3
Determine the quiescent collector current, if the base current is 20 µA.
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The quiescent collector current (
IC) can be determined using the transistor's current gain (
β). Assuming a common
β value, the collector current can be calculated as:
I_C = eta imes I_B
where
I_B = 20 µA. If we take
β = 200, then:
IC=200imes20imes10−6=4extmA
Step 4
Determine the quiescent voltage.
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The quiescent voltage (
V_CE) can be calculated by analyzing the load line in the transistor's output characteristic curves. Assuming a V_CC of 20 V and considering that the collector current is 4 mA:
VCE=VCC−(ICimesRC)
Assuming
R_C to be 2.5 kΩ, we have:
VCE=20V−(4imes10−3imes2500)=10V
Step 5
Include the quiescent point for QUESTION 6.3.3 on the ANSWER SHEET.
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The quiescent point should be marked on the graph with coordinates reflecting
IC = 4 mA and
V_CE = 10 V, representing the operating point where the transistor is biased for optimal operation.
Step 6
Name TWO undesirable effects of transistor biasing in the transistor in FIGURE 6.3 above.
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Two undesirable effects of transistor biasing include:
Thermal runaway, which can occur if the biasing conditions lead to an increase in collector current, resulting in overheating.
Distortion of the output waveform, which can arise from improper biasing and allow for nonlinear operation.
Step 7
Name ONE disadvantage of the RC-coupled amplifier.
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One disadvantage of the RC-coupled amplifier is its unsuitability for low-frequency amplification, as the coupling capacitors block DC signals and reduce gain at lower frequencies.
Step 8
Briefly describe the effect when the temperature of a transistor increases beyond its normal operating points.
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When the temperature of a transistor increases beyond its normal operating points, it leads to an increase in leakage current. This can cause the transistor to enter thermal runaway, potentially damaging it and resulting in failure.
Step 9
Explain why the RC-coupled amplifier can be regarded as a low-frequency filter.
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The RC-coupled amplifier acts as a low-frequency filter because the coupling capacitors block DC and low-frequency signals while allowing higher frequencies to pass. This characteristic allows it to effectively reduce noise and unwanted low-frequency interference.
Step 10
Draw, on the ANSWER SHEET for QUESTION 6.4.4, a fully labeled frequency response curve of the RC-coupled amplifier.
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The response curve should depict the gain in dB versus frequency, highlighting the cutoff frequencies at f1 and f2 where the gain starts to roll off, along with the flat mid-frequency region where the amplifier performs optimally.
Step 11
State ONE disadvantage of the amplifier in FIGURE 6.5 above, besides the cost and the size of the transformer.
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One disadvantage of the amplifier is that it suffers from poor frequency response, affecting the overall quality, especially at high audio frequencies.
Step 12
State the importance of the impedance matching transformer in FIGURE 6.5 above.
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The impedance matching transformer is crucial for maximizing power transfer to the speaker by ensuring that the output impedance of the amplifier matches the impedance of the speaker.
Step 13
State TWO functions of capacitor C1.
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Capacitor C1 serves two key functions:
It allows AC signals to pass through while blocking DC signals, ensuring the proper functioning of the amplifier.
It helps to manage the frequency response of the amplifier by providing coupling between stages.
Step 14
Explain why the output waveform in FIGURE 6.5 is inverted and amplified.
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The output waveform is inverted because of the nature of the transistor's operation in the common emitter configuration, where an increase in input voltage leads to a decrease in output voltage. The amplification is achieved due to the transistor's ability to control a large collector current based on a small base current.
Step 15
Name ONE advantage of the amplifier in FIGURE 6.6 above.
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One advantage of the amplifier is that it produces a much larger output signal than a single Class A biased transistor amplifier, improving efficiency and performance.
Step 16
State NOW cross-over distortion can be eliminated during the operation of the circuit in FIGURE 6.6 above.
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Cross-over distortion can be eliminated by biasing the two push-pull transistors into class AB mode, where both transistors are slightly on during the transition, minimizing the gap and improving linear amplification.
Step 17
Describe the operation of the circuit during the negative half cycle of the input signal.
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During the negative half cycle, transistor Q1 is turned off while Q2 turns on, providing a discharge path for the output. This results in the flow of current through the speaker, producing the negative half of the output waveform.
Step 18
Identify the amplifier circuit from which the frequency response curve in FIGURE 6.7 above is derived.
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The frequency response curve in FIGURE 6.7 is derived from a radio-frequency amplifier that shows bandwidth and gain characteristics.
Step 19
Explain the term bandwidth in relation to the frequency response curve in FIGURE 6.7 above.
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Bandwidth refers to the range of frequencies over which the amplifier maintains an acceptable level of gain. It is defined as the difference between the upper frequency (f2) and lower frequency (f1) at which the gain falls to 70.7% of its maximum value.
Step 20
Briefly describe how resonant frequency can be changed.
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The resonant frequency can be altered by varying the values of either the capacitor or inductor in the tank circuit, which affects the overall resonant condition according to the formula:
f0=2πLC1
Step 21
Name ONE application of the Colpitts oscillator.
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One application of the Colpitts oscillator is in receivers of radio and television, where it generates stable oscillations for signal processing.
Step 22
State the purpose of the tank circuit in FIGURE 6.8 above.
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The tank circuit is essential for determining the frequency of oscillation in the oscillator circuit, acting as a resonant circuit that selectively allows oscillation at a specific frequency.
Step 23
Calculate the oscillating frequency of the circuit in FIGURE 6.8 above when the total capacitance of the tank circuit is 150 µF and the value of the inductor is 200 mH.
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The oscillating frequency can be calculated using the formula:
f0=2πLC1
Substituting:
f0=2π200×10−3×150×10−61≈29.06extkHz
Step 24
State the type of feedback used in FIGURE 6.9 above.
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The type of feedback used in the circuit is positive feedback, which enhances the signal and aids in oscillation.
Step 25
State the value of the phase shift each RC combination produces.
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Each RC combination produces a phase shift of 60 degrees, contributing to the overall feedback mechanism in the oscillator arrangement.
Step 26
Calculate the frequency of oscillation if R1 = R2 = R3 = 10 kΩ and C1 = C2 = C3 = 0.001 µF.
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The frequency of oscillation can be calculated using the formula:
f0=2πRtotalCtotal1
Where:
R_{total} = 3 \times 10kΩ = 30 kΩ
C_{total} = 3 \times 0.001 \mu F = 0.003 \mu F
Substituting the values:
f0=2π×30×103×0.003×10−61≈20.54Hz
Step 27
Explain the term attenuation.
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Attenuation refers to the reduction in amplitude of the output voltage compared to the input voltage. It occurs when a circuit causes a loss of signal power being transmitted, leading to a weaker output.