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5.1 Name the TWO factors that influence the reactance of a capacitor - NSC Electrical Technology Electronics - Question 5 - 2016 - Paper 1

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5.1 Name the TWO factors that influence the reactance of a capacitor. 5.2 Distinguish between the two concepts reactance and impedance. 5.3 Draw the typical freque... show full transcript

Worked Solution & Example Answer:5.1 Name the TWO factors that influence the reactance of a capacitor - NSC Electrical Technology Electronics - Question 5 - 2016 - Paper 1

Step 1

5.1 Name the TWO factors that influence the reactance of a capacitor.

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Answer

The two factors that influence the reactance of a capacitor are:

  1. The frequency of the applied voltage: As frequency increases, the reactance decreases.
  2. The capacitance value: A higher capacitance leads to lower reactance.

Step 2

5.2 Distinguish between the two concepts reactance and impedance.

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Answer

Reactance is the opposition to the change in current caused by inductors and capacitors, while impedance is the total opposition a circuit presents to alternating current, including both resistive and reactive components. Reactance is measured in ohms and can be either capacitive ( Xc) or inductive ( Xl), while impedance is the vector sum of resistance (R) and reactance (X).

Step 3

5.3 Draw the typical frequency/impedance characteristic curve of a series RLC circuit.

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Answer

The frequency/impedance characteristic curve of a series RLC circuit is typically a U-shaped graph where:

  • The vertical axis represents impedance (Z) in ohms.
  • The horizontal axis represents frequency (f) in Hz. At resonance (f_r), the impedance is at its minimum and equals the resistance (R). At lower frequencies, the circuit behaves inductively (Xl > Xc), and at higher frequencies, it behaves capacitively (Xc > Xl).

Step 4

5.4 Calculate the Q-factor of a series RLC circuit that resonates at 6 kHz.

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Answer

To calculate the Q-factor (Q) of the circuit, use the formula: Q=XlZQ = \frac{X_l}{Z} where:

  • At resonance, Xl=Xc=4kΩX_l = X_c = 4 kΩ,
  • The total impedance Z=R=50ΩZ = R = 50 Ω. Thus,

Q=400050=80Q = \frac{4000}{50} = 80.

Step 5

5.5.1 Inductive reactance of the coil.

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Answer

The inductive reactance (XlX_l) can be calculated using the formula: Xl=2πfLX_l = 2\pi f L Substituting the given values: Xl=2π(50)(400×103)=125.66ΩX_l = 2\pi (50)(400 \times 10^{-3}) = 125.66 \Omega.

Step 6

5.5.2 Capacitive reactance of the capacitor.

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The capacitive reactance (XcX_c) can be calculated using the formula: Xc=12πfCX_c = \frac{1}{2\pi f C} Substituting the given values: X_c = \frac{1}{2\pi (50)(47 \times 10^{-6}) = 67.73 \Omega.

Step 7

5.5.3 Frequency at which the circuit will resonate.

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Answer

The resonant frequency (frf_r) can be calculated using the formula: fr=12πLCf_r = \frac{1}{2\pi \sqrt{LC}} Substituting the given values: fr=12π(400×103)(47×106)=36.71Hzf_r = \frac{1}{2\pi \sqrt{(400 \times 10^{-3})(47 \times 10^{-6})}} = 36.71 Hz.

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