Photo AI

4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET) - NSC Electrical Technology Electronics - Question 4 - 2021 - Paper 1

Question icon

Question 4

4.1-Name-ONE-mode-of-operation-of-the-metal-oxide-semiconductor-field-effect-transistor-(MOSFET)-NSC Electrical Technology Electronics-Question 4-2021-Paper 1.png

4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET). 4.2 Refer to FIGURE 4.2 below and answer the questions that follow... show full transcript

Worked Solution & Example Answer:4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET) - NSC Electrical Technology Electronics - Question 4 - 2021 - Paper 1

Step 1

4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET).

96%

114 rated

Answer

The mode of operation can be either Enhancement mode or Depletion mode.

Step 2

4.2.1 Identify the semiconductor symbol in FIGURE 4.2.

99%

104 rated

Answer

The symbol for a MOSFET consists of a gate, drain, and source with a specific representation for each.

Step 3

4.2.2 Explain how the metal-oxide-semiconductor field-effect transistor (MOSFET) differs from the junction field-effect transistor (JFET) with reference to its construction.

96%

101 rated

Answer

The MOSFET has an insulating oxide layer between the gate and the channel, while JFETs have the gate and channel physically connected.

Step 4

4.3.1 Identify puls B2.

98%

120 rated

Answer

Puls B2 is identified as a sawtooth waveform.

Step 5

4.3.2 Explain the term saturation region with reference to the operation of the UJT.

97%

117 rated

Answer

Saturation is the state when the emitter is sufficiently forward biased, causing the UJT to conduct maximally.

Step 6

4.3.3 Describe how the UJT is driven into the CUT-OFF mode.

97%

121 rated

Answer

The UJT enters CUT-OFF when the voltage across the capacitor resets the emitter to a high resistance state.

Step 7

4.4.1 Identify the circuit diagram in FIGURE 4.4.

96%

114 rated

Answer

The circuit diagram is identified as a Darlington transistor amplifier.

Step 8

4.4.2 Describe how the transistors are biased and fully turned ON by referring to the required voltages.

99%

104 rated

Answer

When a voltage exceeding 1.4 V is applied to the base of the Darlington transistor, it is fully turned ON.

Step 9

4.4.3 State TWO advantages of the circuit in FIGURE 4.4.

96%

101 rated

Answer

  1. Provides high current gain. 2. Improves input impedance.

Step 10

4.4.4 Explain why the transistor in FIGURE 4.4 is preferred over a single transistor when used as a switch.

98%

120 rated

Answer

A Darlington configuration provides higher current amplification, making it suitable for loads requiring more current.

Step 11

4.5.1 Identify the type of operational amplifier in FIGURE 4.5.

97%

117 rated

Answer

The operational amplifier is a Non-Inverting Operational Amplifier.

Step 12

4.5.2 Draw the output voltage waveform on the ANSWER SHEET for QUESTION 4.5.2.

97%

121 rated

Answer

The output waveform follows the input waveform, showing amplified variations.

Step 13

4.5.3 Explain why operational amplifiers are known as differential voltage amplifiers.

96%

114 rated

Answer

They amplify the difference in voltage between two inputs, allowing for accurate signal processing.

Step 14

4.6.1 Explain the function of the RS flip-flop.

99%

104 rated

Answer

The RS flip-flop stores binary information and changes states based on input triggers.

Step 15

4.6.2 State the typical operating voltage range of the 555 IC.

96%

101 rated

Answer

The typical operating voltage range of the 555 IC is from +5 V to +15 V or +18 V.

Step 16

4.6.3 Name TWO modes of operation for the 555 IC.

98%

120 rated

Answer

  1. Astable mode. 2. Monostable mode.

Step 17

4.6.5 Explain the function of the threshold input on Pin 6 of a 555 timer IC.

97%

117 rated

Answer

It monitors the voltage at which the IC will reset if exceeded.

Step 18

4.7 Refer to FIGURE 4.7 below and explain why the output is zero volts.

97%

121 rated

Answer

When both inputs are equal, the output cancels out, resulting in an output of zero volts.

Step 19

4.8.1 Calculate the output voltage.

96%

114 rated

Answer

Using the formula: V_{out} = rac{V_{in} imes R_f}{R_n} The output voltage is calculated to be 127.5 mV.

Step 20

4.8.2 Explain the effect on the output when the value of the feedback resistor is equal to that of the input resistor.

99%

104 rated

Answer

The output voltage will be double the input voltage when feedback resistance equals input resistance.

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;