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4.1 Name the semiconductor that is represented by the symbol in FIGURE 4.1 - NSC Electrical Technology Electronics - Question 4 - 2024 - Paper 1

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4.1 Name the semiconductor that is represented by the symbol in FIGURE 4.1. 4.2 Identify sections A and B. 4.3 Identify the MOSFET mode represented in FIGURE 4.3 w... show full transcript

Worked Solution & Example Answer:4.1 Name the semiconductor that is represented by the symbol in FIGURE 4.1 - NSC Electrical Technology Electronics - Question 4 - 2024 - Paper 1

Step 1

Name the semiconductor that is represented by the symbol in FIGURE 4.1.

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Answer

The semiconductor represented by the symbol in FIGURE 4.1 is a P-channel JFET (Junction Field Effect Transistor).

Step 2

Identify sections A and B.

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Answer

Section A is the Silicon dioxide insulation, and Section B is the Enhanced channel.

Step 3

Identify the MOSFET mode represented in FIGURE 4.3 when a positive voltage is applied on the gate.

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Answer

The MOSFET mode represented in FIGURE 4.3 is the Enhancement mode, where the application of a positive voltage creates a conductive channel between the source and drain.

Step 4

State the main difference between the respective modes of operation of a JFET and a MOSFET.

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The main difference is that a JFET operates in the depletion mode, using a reverse-biased gate to control current, whereas a MOSFET can operate in either enhancement mode or depletion mode, providing greater flexibility.

Step 5

State the function of R1 in FIGURE 4.5 above.

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Answer

R1 protects the UJT by limiting the discharge current to a safe value, preventing damage to the device.

Step 6

Briefly describe the operation of the UJT when a negative pulse is applied to the emitter.

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Answer

When a negative pulse is applied to the emitter, the pn junction is reverse biased, which means the emitter current is cut off and the UJT is in the OFF state.

Step 7

Draw the output waveform that would develop across B2 of the UJT as seen in FIGURE 4.5.

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The output waveform across B2 of the UJT will be a saw-tooth waveform, indicating the charging and discharging cycles as the UJT operates.

Step 8

Determine the output state of the op amp in FIGURE 4.6 below for the conditions in TABLE 4.6 below when V2 and V1 are in phase.

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For the given conditions when V2 and V1 are in phase, the output state of the op amp will be positive, indicating that Vout is high.

Step 9

Explain why op amps are not used frequently in open-loop mode.

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Answer

Op amps are not frequently used in open-loop mode because their high gain can lead to instability, making the output voltage highly sensitive to small input variations.

Step 10

Explain the term bandwidth as one of the characteristics of operational amplifiers.

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Answer

The bandwidth refers to the range of frequencies over which an operational amplifier can operate effectively without significant gain loss.

Step 11

Calculate the output voltage.

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Answer

Using the formula Vout=Vin×(RFRin+1)V_{out} = V_{in} \times \left( \frac{R_{F}}{R_{in}} + 1 \right) with Vin=60mV,RF=10kΩ,Rin=1kΩV_{in} = 60 mV, R_{F} = 10 k\Omega, R_{in} = 1 k\Omega, we find: Vout=60×103×(10×1031×103+1)=0.6V=600mVV_{out} = 60 \times 10^{-3} \times \left( \frac{10 \times 10^{3}}{1 \times 10^{3}} + 1 \right) = 0.6 V = 600 mV.

Step 12

Calculate the feedback resistance (Rf) that is needed if the input resistance is 2 kΩ when the op amp is supplied with an input voltage of 0.5 V and produces an output voltage of 4 V.

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Answer

Using the formula RF=Rin×(VoutVin1)R_{F} = R_{in} \times \left( \frac{V_{out}}{V_{in}} - 1 \right) and substituting Vin=0.5V,Vout=4V,Rin=2kΩV_{in} = 0.5 V, V_{out} = 4 V, R_{in} = 2 k\Omega, we get RF=2×103×(40.51)=15.99kΩ16kΩR_{F} = 2 \times 10^{3} \times \left( \frac{4}{0.5} - 1 \right) = 15.99 k\Omega \approx 16 k\Omega.

Step 13

Label pin 7.

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Answer

Pin 7 is the discharge pin.

Step 14

Name ONE application of a 555 IC when used in monostable mode.

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Answer

One application of a 555 IC in monostable mode is as a pulsewidth modulator.

Step 15

Briefly discuss the function of pin 4.

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Answer

Pin 4 is the reset pin for the flip-flop; it resets the output to zero volts when activated.

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