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2.1 Define the term impedance with reference to RLC circuits - NSC Electrical Technology Power Systems - Question 2 - 2018 - Paper 1

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2.1 Define the term impedance with reference to RLC circuits. 2.2 Illustrate the phase relationship between current and voltage by drawing the waveforms of the foll... show full transcript

Worked Solution & Example Answer:2.1 Define the term impedance with reference to RLC circuits - NSC Electrical Technology Power Systems - Question 2 - 2018 - Paper 1

Step 1

Define the term impedance with reference to RLC circuits.

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Answer

Impedance is the total opposition a circuit presents to the flow of alternating current (AC). It combines both resistance (R) and reactance (X), and is measured in Ohms. Mathematically, impedance (Z) is expressed as:

Z=R+jXZ = R + jX

Where:

  • RR is the resistance,
  • XX is the reactance (which can be capacitive or inductive), and
  • jj is the imaginary unit.

Step 2

Illustrate the phase relationship between current and voltage by drawing the waveforms of the following circuits on the ANSWER SHEET.

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Answer

In the case of a pure capacitive circuit, the voltage lags the current by 90 degrees, while in a pure inductive circuit, the current lags the voltage by 90 degrees. These can be represented in graphical waveforms where the sine wave of voltage is shifted.

  • For a capacitive circuit:
    • Voltage Waveform: Starts at 0 and peaks after current.
  • For an inductive circuit:
    • Current Waveform: Starts after the voltage peaks.

Step 3

Calculate the total impedance in the given RLC circuit.

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Answer

To find the total impedance (Z) in the RLC circuit, we use the formula:

Z=R2+(XLXC)2Z = \sqrt{R^2 + (X_L - X_C)^2}

Substituting the given values:

Z=122+(2236)2=122+(14)2Z = \sqrt{12^2 + (22 - 36)^2} = \sqrt{12^2 + (-14)^2} =144+196= \sqrt{144 + 196} =340= \sqrt{340} =18.44Ω= 18.44 \Omega

Step 4

Calculate the current in the RLC circuit.

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Answer

The current (I) can be calculated using Ohm's law:

I=VsZI = \frac{V_s}{Z}

Substituting the values:

I=6018.443.25AI = \frac{60}{18.44} \approx 3.25 A

Step 5

Calculate the Q-factor of the circuit.

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Answer

The Q-factor is calculated using the formula:

Q=VsI×sin(θ)Q = \frac{V_s}{I \times \sin(\theta)}

Here, we know:

  • θ\theta is the angle corresponding to the phase difference (50° in this case), hence:

Q=60×3.25sin(50)149.83Q = \frac{60 \times 3.25}{\sin(50^\circ)} \approx 149.83

Step 6

Explain how frequency affects the inductive reactance.

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Answer

The value of the inductive reactance (!X_L) is directly proportional to the frequency (f) and can be calculated using:

XL=2πfLX_L = 2\pi f L

This means that as frequency increases, the inductive reactance also increases, leading to greater opposition to current.

Step 7

What is the resonant frequency and how does it relate to the circuit?

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Answer

The resonant frequency (f0f_0) is the frequency at which the inductive reactance (XLX_L) equals the capacitive reactance (XCX_C). At this frequency, the circuit can achieve maximum current with minimum resistance. This can be expressed mathematically, and it is a critical point for analyzing RLC circuits.

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