QUESTION 5: THREE-PHASE MOTORS AND STARTERS
5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning - NSC Electrical Technology Power Systems - Question 5 - 2020 - Paper 1
Question 5
QUESTION 5: THREE-PHASE MOTORS AND STARTERS
5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioni... show full transcript
Worked Solution & Example Answer:QUESTION 5: THREE-PHASE MOTORS AND STARTERS
5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning - NSC Electrical Technology Power Systems - Question 5 - 2020 - Paper 1
Step 1
5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning.
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Answer
Check that the bolts securing the motor to the frame are tight.
Ensure that the end plates are fastened properly.
Inspect the bearings for smooth rotation.
Step 2
5.2 State THREE advantages of a squirrel-cage induction motor.
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It is cheaper and more robust compared to other types of motors.
It has slightly higher efficiency and power factor.
These motors are explosion proof, reducing the risk of sparking due to the absence of slip rings and brushes.
Step 3
5.3.1 Identify the control circuit in FIGURE 5.3.
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The control circuit in FIGURE 5.3 refers to a typical motor control circuit, which includes start and stop buttons, contactors, and overload protection components.
Step 4
5.3.2 Explain the function of the following components in FIGURE 5.3:
(a) Stop button
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The function of the stop button is to disconnect the supply from the control circuit and stop both motors.
Step 5
5.3.2 Explain the function of the following components in FIGURE 5.3:
(b) MC₁ (N₀₁)
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The function of MC₁ (N₀₁) is to allow current to flow in the parallel circuit and engage the starting motor, maintaining contact even after the start button is released.
Step 6
5.3.3 Describe the starting sequence of the control circuit.
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When start button 1 is pressed, current flows through the stop button and operating line O₁/L₁.
MC₁ (Motor 1) will energize, and contactors MC₁N₀ and MC₁N₁ will close.
Motor 1 will start running.
When start button 2 is pressed, MC₂ (Motor 2) will energize and close contact MC₂N₁, engaging and switching Motor 2 on.
The two motors will run respectively.
Step 7
5.4.1 Calculate the synchronous speed.
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Answer
The synchronous speed (nₛ) can be calculated using the formula:
ns=p120×f
where:
f=50 Hz, and
p=6 (pole pairs).
Calculating:
ns=6120×50=500 rpm
Step 8
5.4.2 Calculate the rotor speed.
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The rotor speed (nₜ) can be calculated using the formula:
nt=ns×(1−s)
where:
s=0.05 (slip).
Calculating:
nt=500×(1−0.05)=475 rpm
Step 9
5.5.1 Calculate the line current drawn from the supply.
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Answer
The line current (Iₗ) can be calculated using the formula:
Il=1000×Cos θ3×Vl×P
Given:
Vl=380V
P=18kW
Cos θ=0.8
Calculating:
Il=1000×0.83×380×18=34.14A
Step 10
5.5.2 Calculate the apparent power of the motor.
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The apparent power (S) can be calculated using the formula: