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QUESTION 5: THREE-PHASE MOTORS AND STARTERS 5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning - NSC Electrical Technology Power Systems - Question 5 - 2020 - Paper 1

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QUESTION-5:-THREE-PHASE-MOTORS-AND-STARTERS--5.1-State-THREE-mechanical-inspections-to-be-conducted-on-a-three-phase-motor-after-installation,-but-before-commissioning-NSC Electrical Technology Power Systems-Question 5-2020-Paper 1.png

QUESTION 5: THREE-PHASE MOTORS AND STARTERS 5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioni... show full transcript

Worked Solution & Example Answer:QUESTION 5: THREE-PHASE MOTORS AND STARTERS 5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning - NSC Electrical Technology Power Systems - Question 5 - 2020 - Paper 1

Step 1

5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning.

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Answer

  1. Check that the bolts securing the motor to the frame are tight.
  2. Ensure that the end plates are fastened properly.
  3. Inspect the bearings for smooth rotation.

Step 2

5.2 State THREE advantages of a squirrel-cage induction motor.

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Answer

  1. It is cheaper and more robust compared to other types of motors.
  2. It has slightly higher efficiency and power factor.
  3. These motors are explosion proof, reducing the risk of sparking due to the absence of slip rings and brushes.

Step 3

5.3.1 Identify the control circuit in FIGURE 5.3.

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Answer

The control circuit in FIGURE 5.3 refers to a typical motor control circuit, which includes start and stop buttons, contactors, and overload protection components.

Step 4

5.3.2 Explain the function of the following components in FIGURE 5.3: (a) Stop button

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Answer

The function of the stop button is to disconnect the supply from the control circuit and stop both motors.

Step 5

5.3.2 Explain the function of the following components in FIGURE 5.3: (b) MC₁ (N₀₁)

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Answer

The function of MC₁ (N₀₁) is to allow current to flow in the parallel circuit and engage the starting motor, maintaining contact even after the start button is released.

Step 6

5.3.3 Describe the starting sequence of the control circuit.

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Answer

  1. When start button 1 is pressed, current flows through the stop button and operating line O₁/L₁.
  2. MC₁ (Motor 1) will energize, and contactors MC₁N₀ and MC₁N₁ will close.
  3. Motor 1 will start running.
  4. When start button 2 is pressed, MC₂ (Motor 2) will energize and close contact MC₂N₁, engaging and switching Motor 2 on.
  5. The two motors will run respectively.

Step 7

5.4.1 Calculate the synchronous speed.

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Answer

The synchronous speed (nₛ) can be calculated using the formula:

ns=120×fpnₛ = \frac{120 \times f}{p}

where:

  • f=50f = 50 Hz, and
  • p=6p = 6 (pole pairs).

Calculating:

ns=120×506=500 rpmnₛ = \frac{120 \times 50}{6} = 500 \text{ rpm}

Step 8

5.4.2 Calculate the rotor speed.

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Answer

The rotor speed (nₜ) can be calculated using the formula:

nt=ns×(1s)nₜ = nₛ \times (1 - s)

where:

  • s=0.05s = 0.05 (slip).

Calculating:

nt=500×(10.05)=475 rpmnₜ = 500 \times (1 - 0.05) = 475 \text{ rpm}

Step 9

5.5.1 Calculate the line current drawn from the supply.

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Answer

The line current (Iₗ) can be calculated using the formula:

Il=3×Vl×P1000×Cos θIₗ = \frac{\sqrt{3} \times Vₗ \times P}{1000 \times \text{Cos } θ}

Given:

  • Vl=380VVₗ = 380 V
  • P=18kWP = 18 kW
  • Cos θ=0.8\text{Cos } θ = 0.8

Calculating:

Il=3×380×181000×0.8=34.14AIₗ = \frac{\sqrt{3} \times 380 \times 18}{1000 \times 0.8} = 34.14 A

Step 10

5.5.2 Calculate the apparent power of the motor.

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Answer

The apparent power (S) can be calculated using the formula:

S=Vl×Il1000S = \frac{Vₗ \times Iₗ}{1000}

Using the line current calculated previously:

S=3×380×34.14=22.5extkVAS = \sqrt{3} \times 380 \times 34.14 = 22.5 ext{ kVA}

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