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6.1 Name THREE parts of a cage rotor - NSC Electrical Technology Power Systems - Question 6 - 2023 - Paper 1

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6.1 Name THREE parts of a cage rotor. 6.2 Refer to FIGURE 6.2 below and answer the questions that follow. 6.2.1 Identify point X. 6.2.2 Define the term rotor slip... show full transcript

Worked Solution & Example Answer:6.1 Name THREE parts of a cage rotor - NSC Electrical Technology Power Systems - Question 6 - 2023 - Paper 1

Step 1

Identify point X.

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Answer

Point X represents the synchronous speed of the rotor, where the rotor is moving at the same speed as the magnetic field generated by the stator.

Step 2

Define the term rotor slip.

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Answer

Rotor slip is defined as the difference between the synchronous speed and the rotor speed, expressed as a percentage of the synchronous speed. It is given by the formula: ext{Slip} = rac{n_s - n_r}{n_s} imes 100 where nsn_s is the synchronous speed and nrn_r is the rotor speed.

Step 3

Synchronous speed.

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Answer

The synchronous speed (nsn_s) of a motor can be calculated using the formula: n_s = rac{60 imes f}{p} Substituting the values: n_s = rac{60 imes 50}{4} = 750 ext{ r/min}

Step 4

Rotor speed if the slip is 5%.

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Answer

To calculate the rotor speed (nrn_r) with a slip of 5%, we can use the formula: n_r = n_s - rac{ ext{Slip} imes n_s}{100} Calculating: n_r = 750 - rac{5 imes 750}{100} = 712.5 ext{ r/min}

Step 5

Combined true power of the two motors.

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Answer

The combined true power (PtP_t) is given by: Pt=P1+P2=75extkW+50extkW=125extkWP_t = P_1 + P_2 = 75 ext{ kW} + 50 ext{ kW} = 125 ext{ kW}

Step 6

Combined reactive power of the two motors.

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Answer

The combined reactive power (QtQ_t) is obtained by adding the reactive powers: Qt=Q1+Q2=45extkVAr+21.79extkVAr=66.79extkVArQ_t = Q_1 + Q_2 = 45 ext{ kVAr} + 21.79 ext{ kVAr} = 66.79 ext{ kVAr}

Step 7

Apparent power after Motor 2 was added to the system.

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Answer

The apparent power (SS) can be calculated using: S = rac{(P_t)^2 + (Q_t)^2}{ ext{VA}} Calculating: S = rac{(125,000)^2 + (66,790)^2}{ ext{VA}} = 141.72 ext{ kVA}

Step 8

Power factor of the system after Motor 2 was added.

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Answer

The power factor (extpf ext{pf}) can be calculated as: ext{pf} = rac{P_t}{S} = rac{125,000}{141.72 imes 1,000} = 0.88

Step 9

Name the contacts that create the interlocking function in the circuit above.

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Answer

The contacts that create the interlocking function are MC1 N/C and MC2 N/C.

Step 10

Explain why a normally closed contact of the overload is used and not a normally open contact.

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Answer

A normally closed contact allows current to flow under normal operating conditions. If an overload condition occurs, the contact will open, cutting off the current and protecting the motor from damage.

Step 11

Referring to the control mechanisms in the control circuit, explain why MC2 cannot be energised at the same time as MC1.

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Answer

MC2 cannot be energised at the same time as MC1 because the interlocking contact (MC1 N/C) is wired in series with the control circuit for MC2. When MC1 is engaged, the N/C contact for MC1 will open, preventing the energisation of MC2.

Step 12

Explain how the operation of the circuit will be affected when MC1 N/O is faulty and permanently open.

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Answer

If MC1 N/O is faulty and permanently open, it will prevent the energisation of the motor. As a result, pressing the START 1 button will not initiate motor operation, effectively disabling the motor control circuit.

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