2.1 Define the following terms:
2.1.1 Capacitive reactance
2.1.2 Inductive reactance
2.2 FIGURE 2.2 below represents an RLC series circuit that consists of a 25 Ω resistor, a 44 mH inductor and a 120 μF capacitor, all connected across a 120 V/60 Hz supply - NSC Electrical Technology Power Systems - Question 2 - 2019 - Paper 1
Question 2
2.1 Define the following terms:
2.1.1 Capacitive reactance
2.1.2 Inductive reactance
2.2 FIGURE 2.2 below represents an RLC series circuit that consists of a 25 Ω... show full transcript
Worked Solution & Example Answer:2.1 Define the following terms:
2.1.1 Capacitive reactance
2.1.2 Inductive reactance
2.2 FIGURE 2.2 below represents an RLC series circuit that consists of a 25 Ω resistor, a 44 mH inductor and a 120 μF capacitor, all connected across a 120 V/60 Hz supply - NSC Electrical Technology Power Systems - Question 2 - 2019 - Paper 1
Step 1
2.1.1 Capacitive reactance
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Answer
Capacitive reactance is defined as the opposition to an alternating current by the reactive component of a capacitor in an AC circuit. It can be calculated using the formula:
XC=2πfC1
Step 2
2.1.2 Inductive reactance
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Inductive reactance is defined as the opposition to an alternating current by the reactive component of an inductor in an AC circuit. It can be calculated using the formula:
XL=2πfL
Step 3
2.2.1 Inductive reactance
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To calculate the inductive reactance, we use:
XL=2πfL
Substituting the given values:
XL=2π(60)(44×10−3)=16.59Ω
Step 4
2.2.2 Capacitive reactance
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To calculate the capacitive reactance, we use:
XC=2πfC1
Substituting the given values:
XC=2π(60)(120×10−6)1=22.11Ω
Step 5
2.2.3 Impedance of the circuit
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To find the impedance, we utilize the formula:
Z=R2+(XC−XL)2
Substituting the calculated values:
Z=(25)2+(22.11−16.59)2=25.6Ω
Step 6
2.3.1 Calculate the current through the capacitor
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Answer
The current through the capacitor can be calculated using:
IC=XCVS
Substituting the values:
IC=60220=3.67A
Step 7
2.3.2 Calculate the reactive current
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To calculate the reactive current, we use:
IL=IT−IC
Given that IT=6A:
IL=6−3.67=2.33A
Step 8
2.3.3 State whether the phase angle is leading or lagging
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The phase angle is leading because the current through the capacitor leads the voltage across it in an AC circuit. Capacitive circuits result in a leading phase angle.
Step 9
2.4.1 State the value of the capacitive reactance at resonance
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At resonance, capacitive reactance XC equals inductive reactance XL. Therefore, the value is simply equal to XL.
Step 10
2.4.2 Calculate the value of the capacitor at resonance
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To calculate the value of the capacitor at resonance, we use:
C=(2πfXL)1
Substituting for f=1000Hz and XL=50.27Ω:
C=2π(1000)(50.27)1=3.16×10−5F(31.6μF)
Step 11
2.4.3 Explain how the value of the current at resonance will be affected by the supply voltage
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At resonance, the circuit behaves as a purely resistive circuit, and the current is maximum due to the impedance being minimized (only the resistance). If the supply voltage increases, the current will increase proportionally.