Photo AI

3.1 Define phasor diagram with reference to RLC circuits connected across an alternating voltage supply - NSC Electrical Technology Power Systems - Question 3 - 2022 - Paper 1

Question icon

Question 3

3.1-Define-phasor-diagram-with-reference-to-RLC-circuits-connected-across-an-alternating-voltage-supply-NSC Electrical Technology Power Systems-Question 3-2022-Paper 1.png

3.1 Define phasor diagram with reference to RLC circuits connected across an alternating voltage supply. 3.2 FIGURE 3.2 below shows a series RLC circuit which consi... show full transcript

Worked Solution & Example Answer:3.1 Define phasor diagram with reference to RLC circuits connected across an alternating voltage supply - NSC Electrical Technology Power Systems - Question 3 - 2022 - Paper 1

Step 1

Define phasor diagram with reference to RLC circuits connected across an alternating voltage supply.

96%

114 rated

Answer

A phasor diagram is a graphical representation of a sinusoidal alternating current or voltage in an RLC circuit. It helps visualize the relationships between current and voltage in terms of magnitude and phase.

Step 2

Calculate the total supply voltage applied to the circuit.

99%

104 rated

Answer

To find the total supply voltage (V_T), use the formula:

VT=VR2+(VLVC)2V_T = \sqrt{V_R^2 + (V_L - V_C)^2}

Substituting the given values: VT=1502+(18090)2=1502+902V_T = \sqrt{150^2 + (180 - 90)^2} = \sqrt{150^2 + 90^2}

Calculating: VT=22500+8100=30600174.93 VV_T = \sqrt{22500 + 8100} = \sqrt{30600} \approx 174.93 \text{ V}

Step 3

Discuss whether the power factor will be leading or lagging.

96%

101 rated

Answer

The power factor in this circuit is lagging because the inductive voltage (V_L) is greater than the capacitive voltage (V_C). Hence, the overall effect leads to a situation where the voltage lags behind the current.

Step 4

Calculate the total current.

98%

120 rated

Answer

Using the formula for total current in a parallel RLC circuit:

IT=IC2+(ILIR)2I_T = \sqrt{I_C^2 + (I_L - I_R)^2}

Substituting the values: IT=42+(64)2=16+4=204.47AI_T = \sqrt{4^2 + (6 - 4)^2} = \sqrt{16 + 4} = \sqrt{20} \approx 4.47 A

Step 5

Calculate the phase angle.

97%

117 rated

Answer

The phase angle (θ) can be calculated using:

θ=cos1(IRIT)\theta = \cos^{-1}\left(\frac{I_R}{I_T}\right)

Substituting the values: θ=cos1(44.47)26.49\theta = \cos^{-1}\left(\frac{4}{4.47}\right) \approx 26.49^{\circ}

Step 6

Draw the phasor diagram for FIGURE 3.3.

97%

121 rated

Answer

In a phasor diagram for FIGURE 3.3, represent the currents I_C, I_L, and I_R as vectors, and the total current I_T will be the resultant of these vectors. I_T is typically represented at an angle θ from the horizontal reference line.

Step 7

Motivate with a reason if the circuit is predominately capacitive or inductive.

96%

114 rated

Answer

The circuit is inductive because the inductive current (I_L) is greater than the capacitive current (I_C), indicating that the overall effect is determined more by the inductor.

Step 8

Calculate the quality factor of the circuit.

99%

104 rated

Answer

At resonance, X_L = X_C. Using the formula for quality factor (Q):

Q=RXLQ = \frac{R}{X_L}

Substituting known values: Q=220015014.67Q = \frac{2200}{150} \approx 14.67

Step 9

Calculate the bandwidth.

96%

101 rated

Answer

The bandwidth (BW) can be calculated using:

BW=frQBW = \frac{f_r}{Q}

Substituting its value: BW=2,387×10314.67162.82 HzBW = \frac{2,387 \times 10^3}{14.67} \approx 162.82 \text{ Hz}

Step 10

Calculate the value of the capacitor.

98%

120 rated

Answer

Using the resonant frequency equation:

XC=12πfrCX_C = \frac{1}{2 \pi f_r C}

Rearranging gives: C=12πfrXCC = \frac{1}{2 \pi f_r X_C}

Substituting: C=12π×2,387×103×1504.445×107F or 444.51nFC = \frac{1}{2 \pi \times 2,387 \times 10^3 \times 150} \approx 4.445 \times 10^{-7} F \text{ or } 444.51 nF

Step 11

Define the term selectivity with reference to resonant circuits.

97%

117 rated

Answer

Selectivity is a measure of how well a resonant circuit responds to a range of frequencies and excludes others. A high selectivity indicates a narrow bandwidth, meaning the circuit is more sensitive to resonant frequencies.

Step 12

State with a reason the type of component that produces the waveform in FIGURE 3.5 (A).

97%

121 rated

Answer

The waveform in FIGURE 3.5 (A) is produced by an inductor, as indicated by the phase relationship between the voltage and the current, where voltage leads.

Step 13

Identify the power, voltage and current which is dissipated in FIGURE 3.5 (B). Motivate your answer.

96%

114 rated

Answer

The average power in FIGURE 3.5 (B) can be identified by calculating the product of the RMS voltage and current with the power factor. This indicates the real power being dissipated, while the peak values represent the instantaneous power.

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;