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4.1 Refer to FIGURE 4.1 and answer the questions that follow - NSC Electrical Technology Power Systems - Question 4 - 2022 - Paper 1

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4.1 Refer to FIGURE 4.1 and answer the questions that follow. 4.1.1 State whether the phasor diagram represents positive phase sequence or negative phase sequence. ... show full transcript

Worked Solution & Example Answer:4.1 Refer to FIGURE 4.1 and answer the questions that follow - NSC Electrical Technology Power Systems - Question 4 - 2022 - Paper 1

Step 1

4.1.1 State whether the phasor diagram represents positive phase sequence or negative phase sequence. Motivate your answer.

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Answer

The phasor diagram represents positive phase sequence because the direction of rotation is anti-clockwise (R-Y-B phase sequence).

Step 2

4.1.2 Determine whether phasor Vrn represents a line voltage or a phase voltage. Motivate your answer.

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Answer

Phasor Vrn represents a phase voltage because it is the voltage between R (Line 1) and neutral (N).

Step 3

4.2 Explain the term active power.

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Answer

Active power, also known as real power, refers to the capacity of a circuit to perform work at a particular time. It is measured in watts (W) and is the power consumed by resistive loads.

Step 4

4.3 Explain the effect of stepping up the voltage in transmission lines.

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Answer

By stepping up the voltage in transmission lines, the current flowing through the lines is reduced. This reduction in current helps to minimize energy losses due to resistance in the conductors, effectively reducing copper losses.

Step 5

4.4 Draw a diagrammatic representation of a four-wire three-phase star-connected system.

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Answer

    L1
      |
    R----N
      |
    L2
      |
    Y
      |
    L3
      |
    B

Step 6

4.5 Refer to voltages and explain what happens in the distribution stage of the national power grid.

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Answer

In the distribution stage, power is distributed to substations at 22 kV. It is then stepped down to 11 kV for intermediate substations, and finally to 380 V/220 V at distribution substations serving shops, offices, schools, and homes.

Step 7

4.6.1 Phase current of the load.

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Answer

To calculate the phase current, we use the formula:

IPH=IL3I_{PH} = \frac{I_L}{\sqrt{3}}

Thus, IPH=15A38.66A.I_{PH} = \frac{15 A}{\sqrt{3}} \approx 8.66 A.

Step 8

4.6.2 Impedance of the load.

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Answer

To find the impedance of the load, we use:

ZPH=VLIPHZ_{PH} = \frac{V_{L}}{I_{PH}}

Given VL = 400 V,

ZPH=400V8.66A46.19Ω.Z_{PH} = \frac{400 V}{8.66 A} \approx 46.19 \Omega.

Step 9

4.6.3 Phase angle.

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Answer

The phase angle can be determined using the power factor:

cos(θ)=pfθ=cos1(0.85)31.79.\cos(\theta) = pf\Rightarrow \theta = \cos^{-1}(0.85) \approx 31.79^{\circ}.

Step 10

4.6.4 Active power.

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Answer

The active power can be calculated as:

P=3×VL×IL×cos(θ)P = \sqrt{3} \times V_L \times I_L \times \cos(\theta)

Substituting the values:

P=3×400V×15A×0.858833.46W.P = \sqrt{3} \times 400 V \times 15 A \times 0.85 \approx 8833.46 W.

This simplifies to approximately 8.83 kW.

Step 11

4.6.5 Draw a diagram of a power-factor correcting-capacitor bank connected to the three-phase supply in FIGURE 4.6.5.

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Answer

    R   Y   B
    |   |   |
   C1  C2  C3
    |___|___|

Step 12

4.7.1 State TWO advantages of using the three-wattmeter method.

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Answer

  1. It can measure both balanced and unbalanced loads.
  2. The power consumption of each phase can be determined.

Step 13

4.7.2 State ONE disadvantage of the three-wattmeter method.

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Answer

Three wattmeters are required for an unbalanced load. The power factor cannot be determined if no neutral lines exist.

Step 14

4.7.3 Calculate the total power for the reading on W1 = 450 W.

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Answer

For a balanced load, total power is given by:

PT=P1+P2+P3=3×P1=3×450W=1350W.P_T = P_1 + P_2 + P_3 = 3 \times P_1 = 3 \times 450 W = 1350 W.

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