4.1 Refer to FIGURE 4.1 and answer the questions that follow - NSC Electrical Technology Power Systems - Question 4 - 2022 - Paper 1
Question 4
4.1 Refer to FIGURE 4.1 and answer the questions that follow.
4.1.1 State whether the phasor diagram represents positive phase sequence or negative phase sequence. ... show full transcript
Worked Solution & Example Answer:4.1 Refer to FIGURE 4.1 and answer the questions that follow - NSC Electrical Technology Power Systems - Question 4 - 2022 - Paper 1
Step 1
4.1.1 State whether the phasor diagram represents positive phase sequence or negative phase sequence. Motivate your answer.
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Answer
The phasor diagram represents positive phase sequence because the direction of rotation is anti-clockwise (R-Y-B phase sequence).
Step 2
4.1.2 Determine whether phasor Vrn represents a line voltage or a phase voltage. Motivate your answer.
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Answer
Phasor Vrn represents a phase voltage because it is the voltage between R (Line 1) and neutral (N).
Step 3
4.2 Explain the term active power.
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Active power, also known as real power, refers to the capacity of a circuit to perform work at a particular time. It is measured in watts (W) and is the power consumed by resistive loads.
Step 4
4.3 Explain the effect of stepping up the voltage in transmission lines.
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By stepping up the voltage in transmission lines, the current flowing through the lines is reduced. This reduction in current helps to minimize energy losses due to resistance in the conductors, effectively reducing copper losses.
Step 5
4.4 Draw a diagrammatic representation of a four-wire three-phase star-connected system.
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Answer
L1
|
R----N
|
L2
|
Y
|
L3
|
B
Step 6
4.5 Refer to voltages and explain what happens in the distribution stage of the national power grid.
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Answer
In the distribution stage, power is distributed to substations at 22 kV. It is then stepped down to 11 kV for intermediate substations, and finally to 380 V/220 V at distribution substations serving shops, offices, schools, and homes.
Step 7
4.6.1 Phase current of the load.
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Answer
To calculate the phase current, we use the formula:
IPH=3IL
Thus,
IPH=315A≈8.66A.
Step 8
4.6.2 Impedance of the load.
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Answer
To find the impedance of the load, we use:
ZPH=IPHVL
Given VL = 400 V,
ZPH=8.66A400V≈46.19Ω.
Step 9
4.6.3 Phase angle.
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The phase angle can be determined using the power factor:
cos(θ)=pf⇒θ=cos−1(0.85)≈31.79∘.
Step 10
4.6.4 Active power.
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The active power can be calculated as:
P=3×VL×IL×cos(θ)
Substituting the values:
P=3×400V×15A×0.85≈8833.46W.
This simplifies to approximately 8.83 kW.
Step 11
4.6.5 Draw a diagram of a power-factor correcting-capacitor bank connected to the three-phase supply in FIGURE 4.6.5.
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R Y B
| | |
C1 C2 C3
|___|___|
Step 12
4.7.1 State TWO advantages of using the three-wattmeter method.
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It can measure both balanced and unbalanced loads.
The power consumption of each phase can be determined.
Step 13
4.7.2 State ONE disadvantage of the three-wattmeter method.
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Three wattmeters are required for an unbalanced load. The power factor cannot be determined if no neutral lines exist.
Step 14
4.7.3 Calculate the total power for the reading on W1 = 450 W.
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