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QUESTION 3: THREE-PHASE TRANSFORMERS 3.1 State TWO functions of the oil used in oil-filled transformers - NSC Electrical Technology Power Systems - Question 3 - 2016 - Paper 1

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QUESTION 3: THREE-PHASE TRANSFORMERS 3.1 State TWO functions of the oil used in oil-filled transformers. 3.2 Name TWO losses that occur in transformers. 3.3 Stat... show full transcript

Worked Solution & Example Answer:QUESTION 3: THREE-PHASE TRANSFORMERS 3.1 State TWO functions of the oil used in oil-filled transformers - NSC Electrical Technology Power Systems - Question 3 - 2016 - Paper 1

Step 1

3.6.1 Primary line current

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Answer

To calculate the primary line current (IPLI_{PL}), use the formula:

IPL=S3VLPI_{PL} = \frac{S}{\sqrt{3}V_{L_{P}}}

Where:

  • S=20000S = 20000 VA
  • VLP=6600V_{L_{P}} = 6600 V

Substituting the values:

IPL=200003×66001.75AI_{PL} = \frac{20000}{\sqrt{3} \times 6600} \approx 1.75 A

Step 2

3.6.2 Secondary phase voltage

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Answer

To determine the secondary phase voltage (VPHV_{PH}), use the relationship between line voltage (VLSV_{L_{S}}) and phase voltage:

VPH=VLS3V_{PH} = \frac{V_{L_{S}}}{\sqrt{3}}

Substituting the values:

  • VLS=380V_{L_{S}} = 380 V

VPH=3803219.39VV_{PH} = \frac{380}{\sqrt{3}} \approx 219.39 V

Step 3

3.6.3 Transformer ratio

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Answer

The transformer ratio (TRTR) can be calculated using the primary and secondary phase voltages:

TR=VPHVSHTR = \frac{V_{P_{H}}}{V_{S_{H}}}

Where:

  • VPH=6600V_{P_{H}} = 6600 V
  • VSH=380V_{S_{H}} = 380 V

Thus,

TR=660038030:1TR = \frac{6600}{380} \approx 30:1

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